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castortr0y [4]
3 years ago
10

Does spearmint gum have alcohol in it

Physics
1 answer:
Andreyy893 years ago
3 0
Yes it has sugar alcohol
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The heaviest piece of equipment ever carried by plane was 12,400.05kg generator built in Germany in 1993.How far above the groun
nadezda [96]

Answer:

754.6 m

Explanation:

The GPE (Gravitational potential energy) of an object with respect to the ground is given by

GPE = mgh

where

m is the mass of the object

g = 9.8 m/s^2 is the acceleration due to gravity

h is the heigth above the ground

Here we have

m = 12,400.05 kg is the mass

GPE = 91,700,000.00J is the GPE

Solving the formula for h, we find the heigth:

h=\frac{GPE}{mg}=\frac{91,700,000.00J}{(12,400.05 kg)(9.8 m/s^2)}=754.6 m

7 0
4 years ago
You are on an airplane traveling 30° south of due west at 180 m/s with respect to the air. The air is moving with a speed 31 m/s
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1) 211m/s
2)240<span>°
3)759,600m or 759.6 km</span>
6 0
3 years ago
Please help,,, question on image
MA_775_DIABLO [31]

Answer:

first you have to

Explanation:

3 0
3 years ago
Which of the following varies as the electric current varies? The magnetic force decreases The magnetic properties are varied Th
Paladinen [302]
The magnetic properties are varied
6 0
4 years ago
A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.
Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is \mu _{k} = 0.12</h3>

Explanation:

Given :

Initial speed  v_{o} = 9.5 \frac{m}{s}

Displacement x = 37.4 m

From the kinematics equation,

  v^{2} - v^{2} _{o}  = 2ax

Where v^{2}   = final velocity, in our example it is zero (v =0), a = acceleration.

   a =- \frac{90.25}{ 2 \times 37.4}

   a =- 1.21 \frac{m}{s^{2} }

From the formula of friction,

  F =- \mu _{k } N

Minus sign represent friction is oppose the motion

Where N = mg ( normal reaction force )

 ma = -\mu _{k}  m g                                                  ( ∵ g = 9.8 \frac{m}{s^{2} } )

So coefficient of friction,

 \mu_{k} = \frac{1.21}{9.8}

 \mu_{k} = 0.12

Therefore, the coefficient of kinetic friction between the puck and the ice is  \mu _{k} = 0.12 .

4 0
3 years ago
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