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torisob [31]
3 years ago
11

What is the acceleration of a runner who increases her velocity from 2m/s to 8m/s in 3s?

Physics
2 answers:
Tomtit [17]3 years ago
8 0

Answer: 2 m/s^2

Explanation:

V1-Vf/ T

2m/s - 8m/s / 3s

6m/s / 3s =

2 m/s^2

borishaifa [10]3 years ago
3 0
  • initial velocity=u=2m/s
  • Final velocity=v=8m/s
  • Time=t=3s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{8-2}{3}

\\ \sf\longmapsto Acceleration=\dfrac{6}{3}

\\ \sf\longmapsto Acceleration=2m/s^2

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A solid steel ball is thrown directly downward, with an initial speed of 7.95 m/s, from the top of a building at a height of 29.
Anika [276]

Answer:

1.78 s

Explanation:

Initial speed of the ball = u = 7.95 m/s and is vertically downwards.

Acceleration due to gravity = g = 9.8 m/s/s , vertically downwards.

Height of the building  h = 29.8 m (traversed downwards by the steel ball).

h = u t + 1/2 g t²

29.8 = 7.95 t + 0.5 (9.8) t²

⇒ 4.9 t² +7.95 t - 29.8 = 0

Using the quadratic formula , solve for t.

t= = \frac{-b\pm \sqrt{b^2-4\times a \times c}}{2\times a}

t = \frac{-7.95 \pm \sqrt{7.95^2-4\times 4.9 \times (-29.8)}}{2\times 9.8} = 1.78 s, -3.4 s

Since time does not have a negative value, time taken by the stone to reach the ground = t = 1.78 s

5 0
3 years ago
A storage tank contains a liquid at depth y where y=0 when the tank is half full. liquid is withdrawn at a constant flow rate q
Arte-miy333 [17]

Answer:

y(t) = \frac{3Q}{2A} ( t - 1/2 sin2t ) - \frac{Q}{A} t + C

Explanation:

Given data :

storage tank contains a liquid at depth ; Y

when tank is half full ;  y = 0

flow rate = q

sinusoidal rate = 3Q sin^{2} (t)

Determine how the equation can be written for this system

solution is attached below

note ; from the question it can be seen that the surface area ( A )  is constant

5 0
3 years ago
A 1.20x10^3 kilogram car is traveling east at 25 meters per second. the brakes are applied and the car is brought to rest in 5.0
lana [24]

Answer:

F =  7500 N

Explanation:

given,

mass of the car, m = 1200 Kg

initial speed of the car, v = 25 m/s

final speed of car = 0 m/s

time in which car is at rest, t = 5 s

distance = 50 m

Force = ?

using equation of motion for the calculation of acceleration.

 v² = u² + 2 a s

 0² = 25² + 2 x a x 50

100 a = -625

  a = - 6.25 m/s²

negative sign shows deceleration of the car

now, force calculation

F = m  a

F = 1200 x 6.25

F =  7500 N

hence, net force is equal to F =  7500 N

5 0
3 years ago
What will happen to the 0.1 N force if one charges is increased by a factor of 3?
AleksandrR [38]

Answer:

Explanation:

Force between two charges is given by the following expression

F = \frac{KQ_1Q_2}{d^2}  Q₁ and Q₂ are two charges and d is distance between two.

.1 = \frac{KQ_1Q_2}{d^2}

If Q₁ becomes three times , force will become 3 times . Hence force becomes .3 N in the first case.

Force F = .3 N

If charge becomes one fourth , force also becomes one fourth .

F= \frac{.1}{4}

= .025 N.

5 0
3 years ago
A wire carries a current in the x-direction. a positively charged particle moves in the –x-direction near the current-carrying w
Maslowich

A magnetic field is experienced by the charged particle in the +y direction.

Discussion:

  • The right thumb rule states that the magnetic field lines will be perpendicular in the area to the conductive wire's left in which the electric potential is traveling.
  • The direction of the current may be determined by looking at the positive charge's (X direction) motion. According to Fleming's left-hand rule, the force on a positive charge will be in the +y direction because the positive charge is moving in a leftward direction, which will also be the direction of the current.

Fleming's left-hand rule:

In accordance with Fleming's Left Hand Rule, the thumb, forefinger, and middle finger of the left hand should be positioned perpendicular to one another. The thumb should point in the path of the power exerted by the conductors, the forefinger should point in the magnetic field direction, and the middle finger should point in the path of the electric current.

Learn more about the magnetic fields here:

brainly.com/question/14848188

#SPJ4

8 0
2 years ago
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