It's the same as x^211 = 8^152
Simplify that equation. Find the 211th root of (8^152), and that is what x equals. If I remember logs correctly...
The derivative of the function is 2x+6.
At the particular point (2,6), plug in the x coordinate for x.
2(2)+6 = 10
Hope this helps :)
If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
