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3 years ago

How do you subtract and reduce 9 - 2 over 5

2 answers:

4 0

I think once u get ur answer 9-2 then i think u divide your answer by five and then u get your final answer hope that works

Vadim26 [7]3 years ago

3 0

Answer:

8 and 3 over 5

Step-by-step explanation:

first you turn 9 into a improper fraction which is 45 over 5 then you subtract it which equals 43 over 5 and simplified equals 8 and 3 over 5

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Which expression is equivalent to 4/5 divided by 8

notsponge [240]

4/5 divided by 8 is 0.1 other than that I don’t know that question is kind of vague

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3 years ago

Find the area of the shaded region in square units. Show your reasoning.

motikmotik

Answer:

40 square units

Step-by-step explanation:

First of all, lets say that square has side $l$ , so, the area unit is $l^2$

the diagonal's square is $l\sqrt{2}$

CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)

$A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2$

CALCULATION OF MAIN SQUARE AREA

$A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2$

TOTAL AREA

$A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2$

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3 years ago

Please help me will vote the person who does brainiest person or something

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Answer:

quadratic

y=mx+c

Step-by-step explanation:

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3 years ago

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3 years ago

Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3

ehidna [41]

<span>Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3
</span> $\dfrac{x^3+10}{x^3+9}=1+\dfrac{1}{x^3+9} \\ \\ \\ \dfrac{x^3+10}{x^3+9}=\dfrac{(x^3+9)+1}{x^3+9}\\ \\ \\ \dfrac{x^3+10}{x^3+9}=\dfrac{x^3+10}{x^3+9} \\ \\ \\x\in R \qquad x\in (-\infty, +\infty)$ <span>
</span>

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4 years ago