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Anarel [89]
3 years ago
11

Gaucher disease type 1 (GD1 ) is a recessive genetic disease that affects 1 in 900 individuals in a particular population. GD1 i

s caused by a mutation in the enzyme glucocerebrosidase. Assuming the population is in Hardy-Weinberg equilibrium, calculate the frequency of the wild-type (nonmutant) allele for the enzyme glucocerebrosidase.
Biology
1 answer:
dlinn [17]3 years ago
6 0

Answer:

Using the Hardy-Weinberg equilibrium equation, the frequency for the wild-type allele (referred to as <em>p</em>, see explanation below) comes out to be \frac{2}{3}

Explanation:

An individual will have to be homozygous recessive for the mutation in the enzyme glucocerebrosidase to have the Gaucher disease type 1 (GD1). This percentage will be q^{2}

q^{2} = \frac{1}{900} × 100 = \frac{1}{9}

q = \sqrt{\frac{1}{9} } = \frac{1}{3}

We know that \\ p + q = 1 because the sum of both allele frequencies has to be 100%

So \\ 1 - \frac{1}{3} = \frac{2}{3}

Hence, \\ p = \frac{2}{3}

Hope that answers the question, have a great day!

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