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velikii [3]
2 years ago
5

Sodium tungstate is Na₂WO4. Therefore, the formula for gold(III) tungstate is

Chemistry
1 answer:
allsm [11]2 years ago
4 0

Answer:

AuW₃

Explanation:

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PLEASE HELP!! TIMED QUESTION.
BigorU [14]

Answer:

p=m/v

m=mass:402g

v=volume:385ml

p=density:?

divide 402 by 385 to get 1.04 the density is 1.04ml

Density (p)= mass (g)/volume (ml)

5 0
3 years ago
In the reaction CuO(s) + CO2(g) → CuCO3(s), a. CO2 is the Lewis acid and CuCO3 is its conjugate base. b. O2– acts as a Lewis bas
adoni [48]

<u>Answer:</u> The correct answer is Option d.

<u>Explanation:</u>

According to Lewis acid-base concept:

The substance which is donating electron pair is considered as Lewis base and the substance which is accepting electron pair is considered as Lewis acid.

For the given chemical reaction:

CuO(s)+CO_2(g)\rightarrow CuCO_3(s)

CO_2 is accepting electron pair and is getting converted to CO_3^{2-}. Thus, it is considered as Lewis acid.

O^{2-} present in CuO is a Lewis base because it is donating electron pair.

Thus, the correct answer is Option d.

4 0
3 years ago
How many kilowatt-hours of electricity are used to produce 4.50 kg of magnesium in the electrolysis of molten mgcl2 with an appl
ratelena [41]
First, we need to determine the half reaction of magnesium. It would be expressed as:

Mg2+ + 2e- = Mg

Given the mass of magnesium metal that is produced, we calculate the total charge of the electrolysis by the relations we can get from the half reaction. We do as follows:

4.50 kg Mg ( 1000 g / 1 kg ) ( 1 mol / 24.305 g ) ( 2 mol e- / 1 mol Mg ) ( 96500 C / 1 mol e- ) = 35733388.2 C

We are given the applied EMF in units of V. This value is equal to J/C. So, 5 V is equal to 5 J/C.

35733388.2 C (5 J/C) = 178666941 J
178666941 J ( 1 kW-h / 3.6x10^6 J ) = 49.63 kW-h
3 0
3 years ago
Help pls pls pls I really need this answer
blagie [28]

Answer:

I never did this but i think its d 37.5٪ lmk if i got it right pls and srry if i didnt

5 0
3 years ago
60.0 mL of 0.0100 M H3PO4 are required to neutralize 30.0 mL of a solution of KOH. What is the molarity of the potassium hydroxi
Vsevolod [243]

Answer:

h2o

Explanation:

3 0
3 years ago
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