How many molecules of O₂ will be required to produce 28.8 g of water? 2H₂ + O₂ ---> 2H₂O
1 answer:
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Answer: A. 1.60 liters
Explanation:
As can be seen from the balanced chemical equation, 2 moles of produce 1 mole of
.
According to Avogadro's law, every 1 mole of the gas occupies 22.4 liters at STP.
Thus moles of
occupies
at STP and produce 1 mole of
i.e. 22.4 L
44.8 L of will produce 22.4 L of
Thus of
will produce
0.012moldm⁻³
Explanation:
Given parameters:
Mass of AgNO₃ = 1000mg
Volume of water = 500mL
Unknown:
Molarity of solution = ?
Solution:
The molarity of a solution is the number of moles of a solute dissolved in volume of solvent.
Molarity =
Number of moles of AgNO₃ = ?
Number of moles =
Molar mass of AgNO₃ = 108 + 14 + 3(16) = 170g/mol
convert mass to g;
1000mg = 1g
Number of moles = = 0.00588moles
convert the given volume to dm³;
1000mL = 1dm³;
500mL = 0.5dm³
Now solve;
Molarity = = 0.012moldm⁻³
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Molarity brainly.com/question/9324116
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