How do you solve a(3x-8)=b-18?
1 answer:
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First things first, write out your equation without the substitution.
2x+ 2y= 10
Now, put in the substitution.
2x+ 2• 2= 10
Combine like terms.
2x+ 4= 10
Now that your equation it simplified, you need to reverse the problem and put everything on the other side.
2x+ 4= 10
- 4 - 4
2x = 6
2x=6
— —
2 2
X= 3
So the final answer is x=3
2x+ 2y= 10
Now, put in the substitution.
2x+ 2• 2= 10
Combine like terms.
2x+ 4= 10
Now that your equation it simplified, you need to reverse the problem and put everything on the other side.
2x+ 4= 10
- 4 - 4
2x = 6
2x=6
— —
2 2
X= 3
So the final answer is x=3
Given:
Total amount = $10
Cost of loaf of bread = $3.25
Cost of cheese = $5.99 per pound
Each slice weights = 0.04 pounds.
To find:
The inequality for the number of slices that Paul can afford to buy.
Solution:
Let x be the number of slices that Paul can afford to buy.
Weight of on slice is 0.04 pounds. So, weight of x slices is 0.04x pound.
Cost of cheese = $5.99 per pound
So, total cost of cheese for x slices = $5.99 × 0.04x
Now, Paul has $10 to buy bread and cheese for sandwiches. Cost of loaf of bread is $3.25.
Divide both sides by 0.2396.
The maximum integer value of x is 28.
Therefore, the required inequity is and 28 number of slices Paul can afford to buy.