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3 years ago

What is the magnetic force on a proton that is moving at 5.2 x 107 m/s to the

Physics

2 answers:

alisha [4.7K]3 years ago

6 0

Answer:

1.1648×10⁻¹¹ N

Explanation:

Using

F = qvBsinФ..................... Equation 1

Where F = Force on the proton, q = charge, v = velocity, B = magnetic Field, Ф = angle between the magnetic Field and the velocity.

Note: The angle between v and B = 90°

Given: v = 5.2×10⁷ m/s, B = 1.4 T, q = 1.6×10⁻¹⁹ C, Ф = 90°

Substitute into equation 1

F = 1.6×10⁻¹⁹(5.2×10⁷)(1.4)sin90°

F = 11.648×10⁻¹²

F = 1.1648×10⁻¹¹ N.

kogti [31]3 years ago

6 0

Answer:

2.0 x 10^-11

Explanation:

idk if its up or down but look in the comments of this answer, i will put it there when i find out

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A pontoon boat travels across a lake in a straight line and increases in speed uniformly from vi = 18.5 m/s to vf = 36.0 m/s in

omeli [17]

Answer:

Explanation:

a ) The motion is one dimensional , so motion is along x - axis , starting from origin ( 0 , 0 )

b ) Initial velocity is 18.5 m /s when boat is situated at origin . When he displaces by 250 m along x axis and his position is ( 250 , 0 ) along x axis , his velocity becomes 36 m /s . Both his velocity and acceleration is along x - axis.

c ) Initial velocity vi = 18.5 m /s

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Most appropriate formula is given below .

vf² = vi² + 2 a x

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d )

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Required formula

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Putting the values

t = (30 - 18.5) / 1.9

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3 years ago

A 24 kg child descends a 5.0 m high slide and reaches the ground with a speed of 2.8 m/s. What is the mass of the child?

laila [671]

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Explanation:

I did the work. Just plug everything in from the formula. Look at the lesson manual.

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2 years ago