Another name for continuous uniform circular motion is__

What is the mitosis in order?

Sonbull [250]

Answer:

The easy acronym I use to remember this is <u>IPMATC.</u>

Explanation:

Interphase

Prophase

Metaphase

Anaphase

Telophase

Cytokinesis

4 0

3 years ago

What do sodium and fluorine have in common

Anastaziya [24]

They are both in a group of seven of the periodic table

Hope this helps :)

3 0

3 years ago

An interference pattern is produced by light with a wavelength 520 nm from a distant source incident on two identical parallel s

Goshia [24]

Answer:

1) θ = 0.00118 rad, 2) θ = 0.00236 rad , 3) I / I₀ = 0.1738, 4) I / Io = 0.216

Explanation:

In the double-slit interference phenomenon it is explained for constructive interference by the equation

d sin θ = m λ

1) the first order maximum occurs for m = 1

sin θ = λ / d

θ = sin⁻¹ λ / d

let's reduce the magnitudes to the SI system

λ = 520 nm = 520 10⁻⁹ θ = 0.00118 radm

d = 0.440 mm = 0.440 10⁻³ m ³

let's calculate

θ = sin⁻¹ (520 10⁻⁹ / 0.44 10⁻³)

θ = sin⁻¹ (1.18 10⁻³)

θ = 0.00118 rad

2) the second order maximum occurs for m = 2

θ = sin⁻¹ (m λ / d)

θ = sin⁻¹ (2 5¹20 10⁻⁹ / 0.44 10⁻³)

θ = 0.00236 rad

3) To calculate the intensity of the interference spectrum, the diffraction phenomenon must be included, so the equation remains

I = I₀ cos² (π d sin θ /λ ) sinc² (pi b sin θ /λ )

where the function sinc = sin x / x

and b is the width of the slits

we caption the values

x = π 0.310 10⁻³ sin 0.00118 / 520 10⁻⁹)

x = 2.21

I / I₀ = cos² (π 0.44 10⁻³ sin 0.00118 / 520 10⁻⁹) (sin (2.21) /2.21)²

remember angles are in radians

I / I₀ = cos² (3.0945) [0.363] 2

I / I₀ = 0.9978 0.1318

I / I₀ = 0.1738

4) the maximum second intensity is

I / I₀ = cos² (π d sinθ / λ) sinc² (πb sin θ /λ)

x =π 0.310 10⁻³ sin 0.00236 / 520 10⁻⁹)

x = 4.41

I / Io = cos² (π 0.44 10⁻³ sin 0.00236 / 520 10⁻⁹) (sin 4.41 / 4.41)²

I / Io = cos² 6.273 0.216

I / Io = 0.216

.

7 0

3 years ago

Is the tropic of cancer north or south of the equator?

Daniel [21]

It’s North of the equator

3 0

3 years ago

Read 2 more answers

Starting from rest, a small block of mass m slides frictionlessly down a circular wedge of mass M and radius R which is placed o

guapka [62]

Answer:

Part a)

$V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

$v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

$y_{cm} = \frac{mR}{m + M}$

Explanation:

PART A)

As we know that there is no external force on the system of two masses in horizontal direction

So here the two masses will have its momentum conserved in horizontal direction

So we have

$mv + MV = 0$

Also we know that here no friction force on the system so total energy will always remains conserved

So we have

$\frac{1}{2}mv^2 + \frac{1}{2}MV^2 = mgR$

now we have

$\frac{1}{2}m(\frac{MV}{m})^2 + \frac{1}{2}MV^2 = mgR$

$\frac{1}{2}MV^2(\frac{M}{m} + 1) = mgR$

so we have

$V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

and another block has speed

$v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

$y_{cm} = \frac{mR}{m + M}$

7 0

3 years ago

Another name for continuous uniform circular motion is___?