1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Masteriza [31]
3 years ago
12

Another name for continuous uniform circular motion is___?

Physics
1 answer:
VikaD [51]3 years ago
5 0
I think the answer is constant
You might be interested in
List examples of how the Bill of Rights protects you:<br> .<br> .<br> .<br> .<br> .
Naya [18.7K]

guaranteeing freedom of speech, press, assembly, and exercise of religion

4 0
2 years ago
You hold a metal block of mass 40 kg above your head at a height of 2 m.
Kitty [74]

Answer:

The work done by gravity is 784 J.

Explanation:

Given:

Mass of the block is, m=40\ kg

Height to which it is raised is, h=2\ m

Acceleration due to gravity is, g=9.8\ m/s^2

Now, work done by gravity is equal to the product of force of gravity and the distance moved in the direction of gravity. So,

\textrm{Work by gravity}=F_g\times h

Force of gravity is given as the product of mass and acceleration due to gravity.

\therefore F_g=mg=40\times 9.8=392\ N. Now,

\textrm{Work by gravity}=F_g\times h=392\times 2=784\ J

Therefore, the work done by gravity is 784 J.

5 0
3 years ago
Early black-and-white television sets used an electron beam to draw a picture on the screen. The electrons in the beam were acce
lutik1710 [3]

Answer:

speed of electrons = 3.25 × 10^{7} m/s

acceleration in term g is 3.9 × 10^{17} g.

radius of circular orbit is 2.76 × 10^{-4} m

Explanation:

given data

voltage = 3 kV

magnetic field = 0.66 T

solution

law of conservation of energy

PE = KE

qV = 0.5 × m × v²

v = \sqrt{\frac{2qV}{m}}

v = \sqrt{\frac{2\times 1.6 \times 10^{-19}\times 3}{9.1\times 10^{-31}}

v = 3.25 × 10^{7} m/s

and

magnetic force on particle movie in magnetic field

F = Bqv

ma = Bqv

a = \frac{Bqv}{m}  

a =  \frac{0.67\times 1.6\times 10^{-19}\times 3.25\times 10^7}{9.1\times 10^{-31}}

a = 3.82 × 10^{18} m/s²

and acceleration in term g

a = \frac{3.82\times 10^{18}}{9.81}  

a = 3.9 × 10^{17} g

acceleration in term g is 3.9 × 10^{17} g.

and

electron moving in circular orbit has centripetal force

F = \frac{mv^2}{r}  

Bqv = \frac{mv^2}{r}  

r = \frac{mv}{Bq}  

r = \frac{9.1\times 10^{-31}\times 3.25\times 10^7}{0.67\times 1.6\times 10^{-19}}  

r = 2.76 × 10^{-4} m

radius of circular orbit is 2.76 × 10^{-4} m

8 0
3 years ago
100 POINTS WILL GIVE BRAINIEST TO BEST ANSWER!!!!!!!!!!!!!<br><br> see below
gogolik [260]

Answer:

What’s your question

Explanation:

And where

3 0
3 years ago
According to this equation, F=ma, how much force is needed to accelerate an 82-kg runner at 7.5m/s2?
Murljashka [212]
You multiply the mass by the acceleration 82*7.5=615; that's what I would do
5 0
3 years ago
Read 2 more answers
Other questions:
  • A small electronic device is rated at 0.16 W when connected to 115 V. What is the resistance of this device?
    7·2 answers
  • After tasting the salt in the ocean water on a visit to the beach one day, you recall from class that the salt is the __________
    13·2 answers
  • 36 is what percent of 150?<br>​
    12·2 answers
  • A uniformly charged conducting sphere of 1.3 m diameter has a surface charge density of 8.1 µc/m2. (a) find the net charge on th
    9·1 answer
  • Which measurement is a good indicator of physiological age​
    8·2 answers
  • Determine the energy required to accelerate an electron between each of the following speeds. (a) 0.500c to 0.900c MeV (b) 0.900
    12·1 answer
  • What does it mean for a chemical equation to be balanced?
    12·2 answers
  • When an unbalanced force acts on an object
    7·1 answer
  • Please help me guys <br>a.<br>b.<br>c.​
    9·1 answer
  • Construct c = a + b by drawing and calculating the direction and magnitude of c. The direction should be
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!