In atoms, electrons surround the nucleus in

Physics

1 answer:

nasty-shy [4]3 years ago

8 0

In atoms, electrons surround the nucleus in specific energy levels.

Answer: Option B

<u>Explanation: </u>

Atom, actually considered as the tiny part that is ever present in this universe. Many theories and experiments were conducted, for studying what was present inside of an atom, and many theories came into light.

And finally, Bohr-Sommerfeld Theory stated the final conclusion, that the positive charge is at the centre of the nucleus, and all the electrons revolve in their specific energy levels. If an atom wants to move to lower energy state, it should emit energy, whereas for going to higher state, it should gain energy.

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The reason a tennis ball and a solid steel ball will accelerate at the same rate in the absence of air resistance is because why

Tasya [4]

The reason a tennis ball and a solid steel ball will accelerate at the same rate in the absence of air resistance is because the net force to mass ratio is the same for both objects.

<h3>What is air resistance?</h3>

Air resistance is described as the forces that are in opposition to the relative motion of an object as it passes through the air.

The units for the force of air resistance are in Newtons (N).

Air resistance can be gotten by taking air density times the drag coefficient times area all over two, and then multiply by velocity squared.

So we can conclude that in the absence of air resistance, the horizontal velocity of the body is unaffected by any other external force as the only force which acts on the ball is gravity.

Learn more about air resistance at; brainly.com/question/9143942

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7 0

1 year ago

mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan

Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, $v_e$ , for the planet is $v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }$

Where;

$v_e$ = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, $M_E$

r = The radius of the planet = 3 × The radius of Earth, $R_E$

The escape velocity for Earth, $v_e_E$ , is therefore given as follows;

$v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }$

$\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E$