Answer:
yes 20 characters or more
Explanation:
Answer:
Explanation:
Depression = .75 x 10⁻² m
Load = 120 g
Spring constant = 120g / .75 x 10⁻²
= 160 x 10² g / m
b )
Depression by player
= .48 x 10⁻² m
His weight
= .48 x 10⁻² x 160 x 10² g
= 76.8 kg
So he is eligible.
Answer:
A jet pilot puts an aircraft with a constant speed into a vertical loop is explained below in complete details.
Explanation:
Well, the difficulty does not provide the pilot's mass (or weight in regular gravity), but the difficulty can be resolved and declared in courses of m (the pilot's mass).
When the jet is at the foundation of the circuit, a free-body chart displays the centripetal energy working upward approaching the middle of the loop, and the sound force of the chair and the pilot also upward. The pilot's weight (mg) is earthward. From Newton's second law:
?F(c) = ma(c) = n - mg
n = mg + ma(c)
= m[g + a(c)]
Since centripetal acceleration equals v² / r, the equalization enhances:
n = m[g + (v² / r)]
1. Momentum is the product of mass and velocity:
(4 kg)·(8 m/s) = 32 kg·m/s
(Note: the units of kg·m/s tell you this.)
2. Momentum is the product of mass and velocity, so two objects with different masses can have the same momentum if ...
<em>the object with the smaller mass has a greater velocity</em>.
Answer:
a. 1715 N b. 2401 N
Explanation:
Let F = force due to calf muscle, F' = force due to tibia and N = force due to ground = weight of man = mg where m = mass of man = 70 kg and g = acceleration due to gravity = 9.8 m/s².
a. Magnitude of the forces exerted on the foot by the muscle
Since the force due to the calf muscle is 6.0 cm behind the ankle joint and the normal force due to the ground is 15.0 cm in front of the ankle joint and the force due to the tibia is at the ankle joint, taking moments about the ankle joint,
F × 6 cm + F' × 0 cm = N × 15 cm
6F = 15N = 15mg
F = 15mg/6
= 15 × 70 kg × 9.8 m/s²/6
= 1715 N
b. Magnitude of the forces exerted on the foot by the tibia
Taking moments about the calf muscle force, we have
F × 0 cm + F' × 6 cm = N × (15 cm + 6 cm)
6F' = 21N = 21mg
F' = 21mg/6
= 21 × 70 kg × 9.8 m/s²/6
= 2401 N