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Ket [755]
4 years ago
15

In which direction should you look to see the setting moon.

Physics
2 answers:
irina1246 [14]4 years ago
6 0
It depends on the time of day. If it's just after moonrise, look in the east, low in the sky. Then near moonset, look in the west, also low in the sky.
Virty [35]4 years ago
3 0
Every sky object sets in the west.
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What part of the Milky Way allows for determination of its rotational direction? A. Celestial body B. Galactic body C. Galactic
Nitella [24]

Answer: C. Galactic disk

Explanation:

The part of the Milky Way which allows the determination of it rotational direction is known as the Galactic disk. This disc are shaped because they contain gases which are rich and dynamically young. It is also a part of a group of a galaxies disc is a component of disc galaxies, known as spiral galaxies and lenticular galaxies.

5 0
3 years ago
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John pushes his brother Danny on a skateboard. John applies a force of 29 N and Danny's acceleration is 0.4 m/s^2
erastova [34]

The combined mass of Danny+skateboard is 72.5 kg

Explanation:

We can solve the problem by using Newton's second law of motion:

F=ma

where:

F is the net force applied on Danny and the skateboard

m is the mass of Danny+skateboard

a is the acceleration

Here we have the following data:

F = 29 N is the force applied

a=0.4 m/s^2 is the acceleration of Danny and the skateboard

Solving for m, we find their combined mass:

m=\frac{F}{a}=\frac{29}{0.4}=72.5 kg

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

7 0
3 years ago
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All objects in the universe are attracted to each other by the force of. A. effort
stepladder [879]

Answer:

It encapsulates the idea that all the particles of matter in the universe attract each other through the force of gravity – Newton's law tells us how strong that attraction is. ...

Explanation:

your answer

4 0
3 years ago
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HURRY
Mrac [35]

Answer:

It’s b

Explanation:

Everyone else is wrong and I tried this and got it right

6 0
3 years ago
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An object of mass m = 2.9 g and charge Q = +42 µC is attached to a string and placed in a uniform electric field that is incline
Alisiya [41]
(a) 
<span>F= qE </span>

<span>F sin 30.0° = mg </span>
<span>= 0.0026(10) </span>
<span>= 0.026 N </span>
<span>F = 0.052 N </span>

<span>E = F/q = 0.052 / 60µ = 867 N/C </span>

<span>(b) </span>
<span>T = F cos 30.0° </span>
<span>= 0.0450 N</span>
8 0
3 years ago
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