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Sindrei [870]
3 years ago
13

One 10.0 Ω resistor is wired in series with two 10.0 Ω resistors in parallel. A 45.0 V battery supplies power to the circuit. Wh

at is the total current through the circuit?
Physics
2 answers:
shutvik [7]3 years ago
7 0
You can chek this page "<span>Charges électriques - Courant électrique - Eduscol" the lesson is in frensh but you can traduct

</span>
RideAnS [48]3 years ago
4 0
The answer you are looking for 3.0 A
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A wire of length L and cross-sectional area A has resistance R.
lara31 [8.8K]

Answer:

The resistance will be twice the original resistance

Explanation:

This is a fairly simple question, the formular for the resistance of a wire is given as

R = rho *length / area

Where R = resistance

Rho = resistivity

L = length

A = area

Since the density and area are constant I.e they do not change

R/ length = rho/ area

The initial length is given as L, when this length is stretched to twice its original length ,it becomes 2×L = 2L

Let x represent the resistance when the length is doubled

R/ L = x / 2L

x = 2LR / L ; dividing by L

We have that x = 2R ; twice the resistance

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Explanation:

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