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Sindrei [870]
2 years ago
13

One 10.0 Ω resistor is wired in series with two 10.0 Ω resistors in parallel. A 45.0 V battery supplies power to the circuit. Wh

at is the total current through the circuit?
Physics
2 answers:
shutvik [7]2 years ago
7 0
You can chek this page "<span>Charges électriques - Courant électrique - Eduscol" the lesson is in frensh but you can traduct

</span>
RideAnS [48]2 years ago
4 0
The answer you are looking for 3.0 A
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Michael Scott is driving through the parking lot and accidentally hits Meredith as she’s walking to her car. If his car makes co
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Yes she's dead or in the hospital
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3 years ago
If y = 0.02 sin (30x – 200t) (SI units), the frequency of the wave is
leva [86]

Answer:

31.831 Hz.

Explanation:

<u>Given:</u>

  • \rm y = 0.02\sin(30x-200 t).

The vertical displacement of a wave is given in generalized form as

\rm y = A\sin(kx -\omega t).

<em>where</em>,

  • A = amplitude of the displacement of the wave.
  • k = wave number of the wave = \dfrac{2\pi }{\lambda}.
  • \lambda = wavelength of the wave.
  • x = horizontal displacement of the wave.
  • \omega = angular frequency of the wave = \rm 2\pi f.
  • f = frequency of the wave.
  • t = time at which the displacement is calculated.

On comparing the generalized equation with the given equation of the displacement of the wave, we get,

\rm A=0.02.\\k=30.\\\omega =200.\\

therefore,

\rm 2\pi f=200\\\\\Rightarrow f = \dfrac{200}{2\pi}=31.831\ Hz.

It is the required frequency of the wave.

3 0
2 years ago
Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?
zysi [14]

solid

Explanation:

because it has a definite shape and volume

8 0
3 years ago
Using Newton’s second law, why do you think a cotton ball may not be used as a baseball in a baseball game.
stich3 [128]

Answer:

as its mass and velocity will less so its momentum will be less than that of baseball

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3 years ago
What are two ways thermal energy can be increased in a system?
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Adding thermal energy
Performing work on the system
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