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scoray [572]
3 years ago
9

When is the magnitude of the acceleration of a mass on a spring at its maximum value?

Physics
1 answer:
DiKsa [7]3 years ago
6 0

Answer:

D

Explanation:

Now we know that Force is the rate of change of momentum meaning

F= mv/t

But

mv/t = Ke

v/t = ke/m

a= ke/m

Where a is acceleration

K is constant of proportionality of tension on a spring

e is the extension substended by a string.

From the formula of acceleration we can see that as mass decreases acceleration increases so we can see that m = 1

We would have a maximum value of acceleration.

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1. A 1000 kg equipment lift travels up a 200 m shaft in 45 seconds. Assuming the speed is constant, what is the
ANTONII [103]

Answer:

43,555 W

Explanation:

Since the speed is constant, this means that the force applied to lift the equipment is equal to the weight of the equipment. So we can write:

F=mg

where

m = 1000 kg is the mass

g=9.8 m/s^2 is the acceleration due to gravity

So,

F=(1000)(9.8)=9800 N

Then the work done in lifting the equipment is:

W=Fd

where

d = 200 m is the displacement of the equpment

Substituting,

W=(9800)(200)=1.96\cdot 10^6  J

Finally, the power used to lift the equipment is the ratio between the work done and time taken:

P=\frac{W}{t}

where

W=1.96\cdot 10^6 J

t = 45 s is the time taken

Solving,

P=\frac{1.96\cdot 10^6}{45}=43,555 W

8 0
3 years ago
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professor190 [17]

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Explanation:

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