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Ilia_Sergeevich [38]
3 years ago
15

The work done in moving an electron through the 3 ohm resistor is

Physics
1 answer:
Orlov [11]3 years ago
8 0
If the 3 ohm resistor is in parallel to the 12 ohm (I can't see it in the image) then the current through it is 12V/3ohm = 4A  Amps are Coulombs/s  The charge on the electron is 1.6e-19C   So 4 amps means 4/1.6e-19 = 2.5e19 electrons/s.
The reciprocal of this gives the number of electrons per second:
1/2.5e19 = 4e-20 s/(elect. charge)
The power in the 3 ohm resistor is 12*4=48W.  This is Joules/sec.  We know it takes on average 4e-20 s to get one electron charge through the resistor so we multiply:  48W * 4e-20s = 1.9e-18J
Note: In reality there are many electrons moving through the resistor together, and a single electron does not move this fast, but the total energy to do it would be equivalent to this.
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The x and y components of vector S are -30.0 m and +40.0 m, respectively. Find the magnitude of S and the angle between the dire
34kurt

Answer:

The given vector can be represented in unit vector as

\overrightarrow{w}=-30\widehat{i}+40\widehat{j}

The magnitude of any vector \overrightarrow{r}=u\widehat{i}+v\widehat{j} is given by

|w|=\sqrt{u^{2}+v^{2}}

Applying values we get

|w|=\sqrt{-30^{2}+40^{2}}\\\\|r|=50

We know that positive x axis in vertorial form is represented as

\overrightarrow{r}=\widehat{i}

taking dot product of both the vector's we get

\overrightarrow{r}.\overrightarrow{w}=|r||w|cos(\theta )\\\\\therefore cos(\theta )=\frac{(-30\widehat{i}+40\widehat{j}).\widehat{i}}{50}\\\\\therefore \theta =cos^{-1}(\frac{-30}{50})=126.86^{o}

5 0
3 years ago
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How much heat is contained in 100 kg of water at 60.0 °C?
attashe74 [19]
First we need to write down heat capacity for water which is constant.
cp=4186 J/(kg*K)

The equation for Energy that we will be calculating is:

E=cp*m*T
where m is mass and T is absolute temperature (273,15 + 60 in this case). Replacing all the values in equation we get:

E = 4186*100*333,15 = 139 456 590 J
6 0
3 years ago
What is the definition of displacement
Savatey [412]
<span>the action of moving something from its place or position.</span>
6 0
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A wave with a frequency of 14 Hz has a wavelength of 7m. At what speed will this wave travel?
frutty [35]

Answer: A wave with a frequency of 14 Hz has a wavelength of 3 meters. At what speed will this wave travel? 1. = 3m (4. = 42m. 2. ... 1,7m (46) = 7802 m. 4. A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of.

Explanation: please give me brainlest

8 0
3 years ago
(a) At what height above Earth’s surface is the energy required to lift a satellite to that height equal to the kinetic energy r
Nikitich [7]

Answer:

Explanation:

Gravitational Potential Energy at earth surface U_1=\frac{GM_em}{R_e}

Gravitational Potential Energy at height h is U_2=\frac{GM_em}{R_e+h}

Energy required to lift the satellite E_1=U_1-U_2

E_1=\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}

Now Energy required to orbit around the earth

E_2=\frac{1}{2}mv_{orbit}^2=\frac{GM_2m}{2(R_e+h)}

\Delta E=E_1-E_2

\Delta E=\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}-\frac{GM_2m}{2(R_e+h)}

E_1=E_2  (given)

\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}-\frac{GM_2m}{2(R_e+h)}=0

\frac{1}{R_e}-\frac{3}{2(R_e+h)}=0

h=\frac{R_e}{2}

h=3.19\times 10^6\ m

(b)For greater height E_1  is greater than E_2

thus energy to lift the satellite is more than orbiting around earth

4 0
3 years ago
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