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alex41 [277]
3 years ago
14

Which pair of numbers has the greatest common factor of 3?

Mathematics
2 answers:
bearhunter [10]3 years ago
5 0

Answer: 9 and 12

Step-by-step explanation:

AleksandrR [38]3 years ago
5 0

Answer:

9 and 12

<em>I</em><em> </em><em>HOPE</em><em> </em><em>IT</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>YOU?</em><em>:-)</em>

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Write the mixed number 5 2/25 as a percent.
Nataliya [291]

Answer:

I'm assuming it's like this : 5*2/25 which will be 0.4, which is 40%

3 0
3 years ago
FOR AN EXAM DUE TODAY!!!<br><br> Simplify the polynomial.<br> 3x – 2x2 + 4 – x2 + x<br> +<br> -
Mashutka [201]

Answer:

{ \tt{ \blue{  - {3x}^{2} + 4x + 4 }}}

Step-by-step explanation:

{ \tt{3x -  {2x}^{2}  + 4 -  {x}^{2} + x }} \\

» Collect second degree terms (x² coefficients) together and first degree terms (x coefficients) and constants

= { \tt{( - 2 - 1) {x}^{2} + (3 + 1)x + 4 }} \\  = { \boxed{ \tt{ \:  -  {3x}^{2}  + 4x + 4}}}

7 0
3 years ago
Solve x to the second power = 144
vfiekz [6]

x ^ 2 = 144

x = 12, x = -12

Check:

12 * 12 = 144

-12 * -12 = 144

6 0
3 years ago
Read 2 more answers
5000 people voted in an election. Candidate Smith claimed 52% of the votes. Candidate Adams claimed 2681 votes.
SCORPION-xisa [38]

Answer:

Step-by-step explanation:

u got the first 2 correct

percentage of votes Adams claims :

so he claims 2681 out of 5281..

2681 / 5281 = (jeez...u dont want it rounded)...ok....its :

0.50766900208 which equals 50.766900208 % <==

the total of the percentages :

52% + 50.766900208% = 102.766900208 % <==

6 0
3 years ago
Read 2 more answers
Can someone help me please
kifflom [539]

9514 1404 393

Answer:

  {Segments, Geometric mean}

  {PS and QS, RS}

  {PS and PQ, PR}

  {PQ and QS, QR}

Step-by-step explanation:

The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.

  short leg : long leg = SP/RS = RS/SQ   ⇒   RS² = SP·SQ

  short leg : hypotenuse = RP/PQ = PS/RP   ⇒   RP² = PS·PQ

  long leg : hypotenuse = RQ/QP = QS/RQ   ⇒   RQ² = QS·QP

I find it easier to remember when I think of it as <em>the segment from R is equal to the geometric mean of the two segments the other end is connected to</em>.

__

  segments PS and QS, gm RS

  segments PS and PQ, gm PR

  segments PQ and QS, gm QR

4 0
3 years ago
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