Answer:
See below
Step-by-step explanation:
The first one 'cubes' the denominator AND the numerator:
(-2/5)^3 = -2/5 * -2/5 * -2/5 = -8/125
The second one 'cubes' only the denominator:
-2/5^3 = -2 / (5 * 5 * 5) = - 2 / 125
So a general harmonic equation is Asin(2πt/T). Little t is just a variable. 6 inches is the height of one maximum and one minimum from equilibrium, so that is the amplitude A. T is the period, or the time of one cycle (or wavelength), which is 2 seconds.
The equation is therefore (in terms of seconds and inches), 6*sin(2πt/2), or 6*sin(πt).
For the derivative tests method, assume that the sphere is centered at the origin, and consider the
circular projection of the sphere onto the xy-plane. An inscribed rectangular box is uniquely determined
1
by the xy-coordinate of its corner in the first octant, so we can compute the z coordinate of this corner
by
x2+y2+z2=r2 =⇒z= r2−(x2+y2).
Then the volume of a box with this coordinate for the corner is given by
V = (2x)(2y)(2z) = 8xy r2 − (x2 + y2),
and we need only maximize this on the domain x2 + y2 ≤ r2. Notice that the volume is zero on the
boundary of this domain, so we need only consider critical points contained inside the domain in order
to carry this optimization out.
For the method of Lagrange multipliers, we optimize V(x,y,z) = 8xyz subject to the constraint
x2 + y2 + z2 = r2<span>. </span>
Answer:
[(2)^√3]^√3 = 8
Step-by-step explanation:
Hi there!
Let´s write the expression:
[(2)^√3]^√3
Now, let´s write the square roots as fractional exponents (√3 = 3^1/2):
[(2)^(3^1/2)]^(3^1/2)
Let´s apply the following exponents property: (xᵃ)ᵇ = xᵃᵇ and multiply the exponents:
(2)^(3^1/2 · 3^1/2)
Apply the following property of exponents: xᵃ · xᵇ = xᵃ⁺ᵇ
(2)^(3^(1/2 + 1/2)) =2^3¹ = 2³ = 8
Then the expression can be written as:
[(2)^√3]^√3 = 8
Have a nice day!
