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ASHA 777 [7]
4 years ago
14

When a river overflows its banks, it deposits sediment over a broad, flat area of land on both sides of the river. This broad fl

at area is called a _______.
Chemistry
1 answer:
Alex777 [14]4 years ago
3 0
<span>When a river overflows its banks, it deposits sediment over a broad, flat area of land on both sides of the river. This broad flat area is called a floodplain. Floodplains usually have </span><span>areas of higher elevation on both sides</span>
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A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is show
Afina-wow [57]

<u>Answer:</u> The actual yield of the product is 38.57 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

We are given:

Given mass of Na = 17.25 g

Molar mass of Na = 23 g/mol

Putting values in equation 1, we get:

\text{Moles of Na}=\frac{17.25g}{23g/mol}=0.75mol

For the given chemical reaction:

2Na+Cl_2\rightarrow 2NaCl

By stoichiometry of the reaction:

2 moles of Na produces 2 moles of NaCl

So, 0.75 moles of Na will produce = \frac{2}{2}\times 0.75=0.75mol of NaCl

We know, molar mass of NaCl = 58.44 g/mol

Putting values in above equation, we get:

\text{Mass of NaCl}=(0.75mol\times 58.44g/mol)=43.83g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ......(1)

Given values:

Percent yield of the product = 88 %

Theoretical value of the product = 43.83 g

Plugging values in equation 1:

88\% =\frac{\text{Actual yield}}{43.83g}\times 100\\\\\text{Actual yield}=\frac{88\times 43.83}{100}=38.57g

Hence, the actual yield of the product is 38.57 g

3 0
3 years ago
A scientist produces zinc iodide (zni2). (a) calculate the minimum mass of zinc that needs to be added to 0.500 g of iodine so t
harina [27]

The minimum mass of Zinc, Zn that needs to be added to 0.500 g of iodine so that the iodine fully reacts is 0.128 g

<h3>Balanced equation </h3>

Zn + I₂ —> ZnI₂

Molar mass of Zn = 65 g/mol

Mass of Zn from the balanced equation = 1 × 65 = 65 g

Molar mass of I₂ = 127 × 2 = 254 g/mol

Mass of I₂ from the balanced equation = 1 254 = 254 g

SUMMARY

From the balanced equation above,

254 g of I₂ required 65 g of Zn

<h3>How to determine the mass of Zn needed </h3>

From the balanced equation above,

254 g of I₂ required 65 g of Zn

Therefore,

0.5 g of I₂ will require = (0.5 × 65) / 254 = 0.128 g of Zn

Thus, the minimum mass of Zn required is 0.128 g

Learn more about stoichiometry:

brainly.com/question/14735801

4 0
3 years ago
If element X has 25 protons, how many electrons does it have?
igor_vitrenko [27]
Im pretty sure it would also be 25
7 0
4 years ago
Read 2 more answers
87 g of oxygen gas would occupy how many liters of volume at stp
loris [4]
Number of mole : mass/ molar mass

87g/ (2 x 16) = 2.719 mol

volume = number of mole x molar volume
volume = 2.719 x 22.4
volume = 60.906 L
8 0
4 years ago
What is the formula for Iodine Pentafluride?
Allushta [10]

Answer:

It's IF5. ................

7 0
3 years ago
Read 2 more answers
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