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3 years ago

Vocabulary matching - science . PLEASE HELP !!!

Physics

2 answers:

ddd [48]3 years ago

8 0

Answer:

1. kinetic energy

2.speed

3.motion

4.mass

5.energy transfer

hope this helped!!

mihalych1998 [28]3 years ago

8 0

1. Kinetic energy
2. Speed
3. Motion
4. Mass
5. Energy Transfer
Hope this help

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From hottest to coolest, the order of the spectral types of stars is _________. From hottest to coolest, the order of the spectr

Dimas [21]

Answer:

OBAFGKM

Explanation:

Most stars are classified using the Morgan-Keenan system, which consists of assigning a letter to the star depending on its temperature. The hottest stars are type O, and the coldest stars are type M. As for their color, the coldest stars tend to have red color and the hottest have blue colors.

Within each of these divisions (OBAFGKM), there is another division that are the numbers from 0 to 9: 0 is hotter and 9 colder, to get a better classification of a star.

The order of the letters of the Morgan – Keenan system classification, according to the temperatures is as follows:

O: temperatures greater than 33,000K

B: temperatures between 10,000K and 33,000K

A: temperatures between 7,500K and 10,000K

F: temperatures between 6000K and 7.500K

G: temperatures between 5,200K and 6,000K

K: temperatures between 3,700k and 5,200K

M: temperatures below 3,700 K

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4 years ago

Two very long uniform lines of charge are parallel and are separated by 0.300 m. each line of charge has charge per unit length

Alenkasestr [34]

linear charge density of system of two line charges is given as

$\lambda = 5.20 \muC/m$

now as we know that electric field due to a line charge at some distance from it is given by

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

so here we will first find the electric field of first line charge at the position of other line charge

$E = \frac{5.20 * 10^{-6}}{2 \pi * 8.85 * 10^{-12}* 0.300}$

$E = 312000 N/C$

now as we know that

$F = qE$

here q = charge on the line charge system at which force is required

E = electric field on that system of charge where force is required

now we can find the charge by

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$q = 5.20 * 10^{-6}* 0.05 = 0.26 * 10^{-6} C$

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$F = qE$

$F = 0.26 * 10^{-6} * 312000$

$F = 0.0811 N$

so force on the part of wire is F = 0.0811 N

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Answer:

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system.

Explanation:

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