1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Drupady [299]
3 years ago
6

The fossils of a few organisms are shown below. The first image is a bird, the second image is a dinosaur, and the third image i

s an Archaeopteryx. The dinosaur fossils were obtained from the lower sedimentary layer, and Archaeopteryx was found above it. The fossils of the bird were found on the topmost layer, which suggests that they’re the BLANK . This information also suggests that Archaeopteryx BLANK.
BLANK 1 options
youngest fossils
oldest fossils
same age as the other fossils
BLANK 2 options
evolved from birds
came after dinosaurs but before birds
evolved before nonflying dinosaurs
Physics
1 answer:
Cloud [144]3 years ago
3 0

youngest fossils

came after dinosaurs but before birds

Explanation:

From the information provided us in the description we know that the fossils of the bird in the topmost layer suggests that they are the youngest fossils and those of the archaeopteryx came before the birds but after the dinosaurs.

According to the information we have, the sequence of the formation of the fossils are:

                       Bird                                youngest

                       Achaeopteryx

                       Dinosaurs                        oldest

This resolution is based on the principle of fossil and faun succession "fossils and fauna succeed one another in a definite pattern".

learn more:

Fossils brainly.com/question/9415077

#learnwithBrainly

You might be interested in
What is the initial velocity and final velocity<br> h
IceJOKER [234]

Answer:

initial velocity =starting velocity

final velocity=last velocity

keep in mind the fact that  velocity is a vector quantity it also has a direction

8 0
3 years ago
An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below
grin007 [14]
<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let P be the pressure at a point.

Let p be the density fluid at a point.

Let v be the velocity of fluid at a point.

Bernoulli's equation states that P+\frac{1}{2}pv^{2}+pgh=constant for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let p_{up} be the pressure of a point just above the wing.

Let p_{do} be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}

So,p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa

Force is given by the product of pressure difference and area.

Given that area is 27ms^{2}.

So,lifting force is 16398.48\times 27=442758.96N

6 0
4 years ago
A car travels 2155.0m in 195.9s. What is the car's average speed?
inna [77]

Average speed of the car is 11 m/s

Explanation:

  • Speed is calculated by the rate of change of displacement.
  • It is given by the formula, Speed = Distance/Time
  • Here, distance = 2155 m and time = 195.9 s

Speed of the car = 2155/195.9 = 11 m/s

3 0
4 years ago
A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo
zloy xaker [14]

Solution :

Given :

Mass attached to the spring = 4 kg

Mass dropped = 6 kg

Force constant = 100 N/m

Initial amplitude = 2 m

Therefore,

a). $v_{initial} = A w$

          $= 2 \times \sqrt{\frac{100}{4}}$

          = 10 m/s

Final velocity, v at equilibrium position, v = 5 m/s

Now, $\frac{1}{2}(4+4)5^2 = \frac{1}{2} kA'$

A' = amplitude = 1.4142 m

b). $T=2 \pi \sqrt{\frac{m}{k}}$

    m' = 2m

    Hence, $T'=\sqrt2 T$

c). $\frac{\frac{1}{2}(4+4)5^2 + \frac{1}{2}\times 4 \times 10^2}{\frac{1}{2} \times 4 \times 10^2}$

  $=\frac{1}{2}$

Therefore, factor $=\frac{1}{2}$

Thus, the energy will change half times as the result of the collision.

7 0
3 years ago
I have a combination of myopia and presbyopia—overall, the power of my visual system is too large, but I also have a very limite
e-lub [12.9K]

Answer:

The range of powers is    - 5 \ D \le P \le - 2.667\  D

Explanation:

From the question we are told that

       The far point of the left eye is n_f = 20 cm

       The near point of the left eye is  n =  15cm

       The near point with the glasses on is n_g =25 \ cm

     

From these parameter we can see that with the glass on that for near point the

         Object distance would be u = -25 \ cm

          Image distance would be  v =  -15 \ cm

To obtain the focal length we would apply the lens formula which is mathematically represented as

              \frac{1}{f} =  \frac{1}{v}  -  \frac{1}{u}

substituting values

              \frac{1}{f} =  \frac{1}{-15}  -  \frac{1}{-25}

               f =  - \frac{75}{2} cm

           converting to  meters

               f =  - \frac{75}{2} * \frac{1}{100}

               f =  - \frac{75}{200} \ m

   Generally the power of the lens is mathematically represented as

                P  = \frac{1}{f}

Substituting values

                 P = -  \frac{200}{75}  m

                 P = - 2.667 \ D

   

From these parameter we can see that with the glass on that for far  point the

         Object distance would be u_f = - \infty \ cm

          Image distance would be  v_f =  -20  \ cm

To obtain the focal length of the lens we would apply the lens formula which is mathematically represented as

                    \frac{1}{f_f} =  \frac{1}{v_f}  -  \frac{1}{u_f}

substituting values

                  \frac{1}{f} =  \frac{1}{-20}  -  \frac{1}{- \infty}

                 \frac{1}{f} =  \frac{1}{-20}  -  0      

                  f_f =  \frac{20}{1}  \ cm

converting to  meters

                f_f =  - \frac{20}{1}  * \frac{1}{100}

               

Generally the power of the lens is mathematically represented as

                P  = \frac{1}{f_f}

Substituting values

                 P = -  \frac{100}{20}  m

                 P = - 5 \ D

This implies that the range of powers of the lens in his glass is

                  - 5 \ D \le P \le - 2.667\  D

   

               

               

           

3 0
4 years ago
Other questions:
  • If you let go of the notebook after pushing it, will it move?​
    5·1 answer
  • How does temperature change affect surface tension
    10·1 answer
  • This is a small rocky body that orbits the sun, and when close to the sun exhibit a small tail of ice and gas.
    7·1 answer
  • An 8 kilogram bowling ball is rolling in a straight line toward you. if its momentum is 16 kg* m/s, how fast is it traveling ?
    9·1 answer
  • Explain how the atmosphere and hydrosphere interact to create weather
    8·1 answer
  • JUST PLZ HELP!!! Why does the lightbulb in the right electrical circuit turn on but not the one on the left?
    14·2 answers
  • A particle with charge − 3.74 × 10 − 6 C is released at rest in a region of constant, uniform electric field. Assume that gravit
    7·1 answer
  • 3. Which of the following statements is not true about Gauss’s law?
    13·2 answers
  • What are the advantages of atmospheric pressure?​
    7·2 answers
  • How does the electric force between two charged particles change if the
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!