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3 years ago

Diffraction occurs when waves _____ after passing through an opening

Physics

2 answers:

saw5 [17]3 years ago

8 0

The answer to your question is A

OleMash [197]3 years ago

7 0

Answer:

a. spread

Explanation:

hope dis helps! :)

§ALEX§

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Venus has about the same mass as Earth and is about the same distance from the Sun. Yet Venus does not support life. An importan

Bogdan [553]

The correct answer is: (A) An Atmosphere

Explanation:
The atmosphere of Venus is almost ninety times denser than that of Earth. Due to Venus' denser atmosphere and chemical composition (as its atmosphere comprises of over 96% of Carbon dioxide), it experience an immense greenhouse effect. That is why its surface temperature remains higher than 470°. At that very high temperature, it is impossible to have life on the surface of Venus.

8 0

2 years ago

Read 2 more answers

Newton’s law of universal gravitation stars that every object in the universe attracts every other object

LenaWriter [7]

Yes it does ! Uh huh. Right you are. Truer words are seldom written.

You have quoted the law quite accurately but also incompletely.

Do you have a question to ask ?

4 0

2 years ago

Claudia uses 100 N of force on a rope attached to a pulley to lift an anvil that weighs 400 N. What is the Mechanical Advantage

Mashcka [7]

Answer:

100 N/ 400 N= .25

Explanation:

7 0

3 years ago

A high-speed flywheel in a motor is spinning at 450 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and

alexira [117]

Answer:

A) $\omega_f=17.503\ rad.s^{-1}$

B) $t=55.6822\ s$

C) $\theta=1312\ rad$

Explanation:

Given:

mass of flywheel, $m=40\ kg$

diameter of flywheel, $d=0.72\ m$

rotational speed of flywheel, $N_i=450\ rpm \Rightarrow \omega_i=\frac{450\times 2\pi}{60} =15\pi\ rad.s^{-1}$

duration for which the power is off, $t_0=35\ s$

no. of revolutions made during the power is off, $\theta=180\times 2\pi=360\pi\ rad$

<u>Using equation of motion:</u>

$\theta=\omega_i.t+\frac{1}{2} \alpha.t^2$

$360\pi=15\pi\times 35+\frac{1}{2} \times \alpha\times35^2$

$\alpha=-0.8463\ rad.s^{-2}$

Negative sign denotes deceleration.

Now using the equation:

$\omega_f=\omega_i+\alpha.t$

$\omega_f=15\pi-0.8463\times 35$

$\omega_f=17.503\ rad.s^{-1}$ is the angular velocity of the flywheel when the power comes back.

Here:

$\omega_f=0\ rad.s^{-1}$

Now using the equation:

$\omega_f=\omega_i+\alpha.t$

$0=15\pi-0.8463\times t$

$t=55.6822\ s$ is the time after which the flywheel stops.

Using the equation of motion:

$\theta=\omega_i.t+\frac{1}{2} \alpha.t^2$

$\theta=15\pi\times 55.68225-0.5\times 0.8463\times 55.68225^2$

$\theta=1312\ rad$ revolutions are made before stopping.

3 0

3 years ago

How an application of atmospheric device work?example siphon

Vika [28.1K]

Answer:

A practical siphon, operating at typical atmospheric pressures and tube heights, works because gravity pulling down on the taller column of liquid leaves reduced pressure at the top of the siphon (formally, hydrostatic pressure when the liquid is not moving).

I hope it's helpful!

6 0

2 years ago