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jonny [76]
3 years ago
8

Torque can be calculated by multiplying the force ( n ) applied at 90 â to the lever arm at a distance ( m ) from the pivot poin

t (point of rotation), the compound si unit for the torque is nâm . if the force (at 90 â to the lever arm) applied is 15 n and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?
Physics
2 answers:
JulijaS [17]3 years ago
8 0

Answer:

The torque on the lever is 30.0 N m.

Explanation:

Torque is defined as tendency of a force to rotate a body around its axis. Mathematically written as:

\tau=Force\times d\times \sin \theta

Force applied on the lever arm at 90°= 15 N

Distance at which force is applied = d = 2.0 m

\tau =15 N\times 2.0 m\times \sin 90^o= 30.0 N m

The torque on the lever is 30.0 N m.

Marianna [84]3 years ago
3 0

The Torque on the lever is 30Nm.

<h2>Further Explanation: </h2>

Torque

  • It is a measure of the amount of force acting on an object that causes the object to rotate about an axis.
  • Torque is a vector quantity, in the sense that it has both magnitude and direction.
  • Example of torque; when a push is applied on a door, then the distance to the hinge is the perpendicular distance, meaning it is at 90 degrees to the force arrow.
<h3>Calculation of Torque </h3>
  • Torque is calculated by the formula;

T = F x r sin θ

Where r is the length of the moment arm, F is the force making an object to rotate and θ is the angle between the force vector and the moment arm.

  • When the force is at right angles to the moment arm then the sin is 1 and the formula becomes;

Torque = F x r

The S.I. units of torque is Newton-meter.

<h3>In the question; </h3>

Force applied at the lever arm is 15 N  

Distance from the axis of rotation to the force vector is 2.0 m

Angle between the vector force and the moment arm is 90  

Therefore;

Torque = Force x perpendicular distance  

             = 15 N x 2.0 m

            = 30 Nm  

Therefore; The Torque on the lever is 30 Nm

Keywords: Torque, Force, length of the arm  

<h3>Learn more about:  </h3>
  • Torque: brainly.com/question/1621931
  • Examples of Torque; brainly.com/question/2136775

Level: High school  

Subject: Physics  

Topic: Turning effects of Force

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Find the moment of inertia about each of the following axes for a rod that is 0.36 cm in diameter and 1.70m long, with a mass of 5.00 × 10 ^(−2) kg.

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