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3 years ago

HELP Me Please I will give 20 points

Chemistry

2 answers:

lisabon 2012 [21]3 years ago

5 0

Answer:

Explanation:

uysha [10]3 years ago

5 0

Answer:

1 to C

2 to A

3 to B

Explanation:

I hope this helps

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How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?

RoseWind [281]

The chemical reaction would be as follows:

2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
105 g S ( 1 mol / 32.06 g ) = 3.28 mol S

The limiting reactant would be Na. We calculate as follows:

1.97 mol Na ( 1 mol Na2S / 2 mol Na ) (78.04 g / mol ) = 76.87 g Na2S produced

8 0

3 years ago

30) Which of these statements are true?

Katen [24]

D) 1 and 4
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4 0

3 years ago

Read 2 more answers

Read that From picture and tell me the answer please

Dafna11 [192]

Answer:

1g Hydrogen

Explanation:

<h3>Getting to the equation:</h3>

Calcium in water reacts vigorously to give a cloudy white Precipitate (compound) called Calcium hydroxide alongwith the evolution of Hydrogen gas.

$\boxed{ \mathsf{Ca + H_2O \rightarrow Ca(OH)_2 + H_2}}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Balancing the equation: </h3>

This reaction is not in it's balanced form! The number of atoms of Hydrogen on the left is 2 while that on the right is 4,I.e.,they're not equal.

Adding a 2 in front of H2O solves the problem by making the number of atoms of each element on both the sides equal.

$\mathsf{Ca +2 H_2O \rightarrow Ca(OH)_2 + H_2}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Observations:</h3>

Looking into the equation more carefully, we see:

1 atom of Calcium reacts with 2 molecules of water to give 1 molecule of Calcium Hydroxide alongwith 1 molecule of Hydrogen gas.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Gram atomic and molecular masses </h3>

Mass of one atom of Calcium = it's gram atomic mass

= 40 g

Mass of one "molecule" of Hydrogen

= it's Gram molecular mass

= gram mass of one atom × number of atoms in one molecule

= 1 × 2

= 2 g

So,

according to our observation:

One atoms of Calcium gives one molecule of Hydrogen (during the particular reaction)

=> 40g of Calcium gives = 2g of Hydrogen

•°• 1 g of Calcium gives = $\frac{2}{40}$

= $\frac{1}{20}$ g Hydrogen

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<h3>Answer:</h3>

We're provided with 20g of Calcium,

=> 20g of Calcium gives = 20 × $\frac{1}{20}$ g H2

= 1 g H2

_______________

Hope this helps!

6 0

2 years ago

ASAPP Subtract to find the temperature changes

mamaluj [8]

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4 0

3 years ago

Identify the limiting reactant when 32. 0 g hydrogen is allowed to react with 16. 0 g oxygen

Mkey [24]

Answer:

Oxygen is limiting reactant

Explanation:

2 H2 + O2 ======> 2 H2 O

from this equation (and periodic table) you can see that

4 gm of H combine with 32 gm O2

H / O = 4/32 = 1/8

32 /16 = 2/1 shows O is limiter

for 32 gm H you will need 256 gm O and you only have 16 gm

3 0

2 years ago