Answer:
2.8248 g
Explanation:
First, consider the balanced chemical equation:
Then we calculate the number of moles in 4.11 g of citric acid:
n(citric acid)=
According to the balanced reaction, one mole of citric acid produces 3 moles of carbon dioxide. That's 3 times the number f moles of citric acid. So we will do the same with the available number of moles of citric acid.
so n(carbon dioxide) = 0.0214 mol*3=0.0642 mol
mass(carbon dioxide)= mass*molar mass=0.0642 mol* 44g/mol
= 2.8248 g
I assume that the experiment is about calculating the enthalpy of a reaction.
If you consistently use the thermometer for all procedure in the experiment, the effect will be negligible because all temperature will be increased by 1.5 °C.
In enthalpy calculation, the energy is determined by the temperature differences. If the final and initial temperature increased by 1.5 °C, then the difference will not be changed.
<h3>
Answer:</h3>
1.83 × 10⁻⁷ mol Au
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.60 × 10⁻⁵ g Au (Gold)
<u>Step 2: Identify Conversions</u>
Molar Mass of Au - 196.97 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au
Answer:
The answer to your question is n = 5, l = 2, m can be -2, -1, 0, 1 or 2
Explanation:
Data
orbital = 5d
values of n, l, m
Process
1.- Determine the value of n
n is the coefficient of the orbital, in this problem n = 5
2.- Determine the value of l
l takes values depending in the sublevel of energy,
if the sublevel is s then l = 0
p l = 1
d l = 2
f l = 3
For this problem l = 2
3.- Determine the value of m
when l = 2, m takes values of -2, - 1, 0, 1 or 2
