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3 years ago

9

How many atoms of each element are in the chemical formula NH4NO2?

1 answer:

Alika [10]3 years ago

3 0

5 nitrogen, 1 hydrogen, and 1 oxygen I think

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Balance the following equation and determine the coefficients in order

Juliette [100K]

Answer:

D 4,3,2

Explanation:

4 Co + 3 O2 ----> 2 Co2O3

7 0

3 years ago

What are six forms of energy? Find an example of each.

Evgesh-ka [11]

1-Electric Energy
Example: A lightbulb is an example of electric energy
2-Sound Energy
Example: When a dog barks, that is sound energy
3-Solar Energy
Example: When we use the sun for energy. Like using it to dry our clothes.
4-Chemical Energy
Example: An example is a battery. That may not seem like it, but it is Chemical Energy.
5-Nuclear Energy
Example: A fission reaction at a nuclear powerplant
6-Thermal Energy
Example: A pot of water boiling on an Electric Stove
~Silver

4 0

3 years ago

What are resources?

Georgia [21]

Answer:

A resource is a source or supply from which a benefit is produced.

Explanation:

hope it helped :)

6 0

3 years ago

Calculate the average weight of the dogs listed in the chart below.

pishuonlain [190]

Answer:

19

Explanation:

Once you add all the weights together, you end up with 114 then you divide it by how many dogs there are, 6. 114/6 = 19. The average is 19 lbs.

3 0

3 years ago

Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the

Alecsey [184]

Explanation:

The chemical equation is as follows.

$\frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)$

And, the given enthalpy is as follows.

$\frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g)$ ; $\Delta H$ = 102.5 kJ

Cl-Cl = 243 kJ/mol, O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

$\Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}$

102.5 = $[(\frac{1}{2})x + 498] - [(2)(243)]$

102.5 = $(\frac{1}{2})x + 498 - 486$

102.5 - 12 = $\frac{x}{2}$

x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

$\Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})$

x = $[(\frac{1}{2})181 + (\frac{1}{2})498] - 243$

= 339.5 - 243

= 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0

3 years ago