Answer:
This is a precipitation reaction in which Ni(OH)₂ precipitates.
8.68%
Explanation:
Let's consider the following reaction.
Ni²⁺(aq) + 2 NaOH(aq) ⇄ Ni(OH)₂(s) + 2 Na⁺(aq)
This is a precipitation reaction in which Ni(OH)₂ precipitates.
We can establish the following relations:
- The molar mass of Ni(OH)₂ is 92.71 g/mol.
- 1 mole of Ni(OH)₂ is produced per 1 mole of Ni²⁺.
- The molar mass of Ni²⁺ is 58.69 g/mol.
When 343 mg (0.343 g) of Ni(OH)₂ are collected, the mass of Ni²⁺ that reacted is:
The mass percent of nickel in the 25.0g-sample is: