Answer:
The answer is 3.48 seconds
Explanation:
The kinematic equation
y= y0+V0*t+1/2*a*(t*t)
-50=0+(0)t+1/2(-9.8)*(t*t)
t=3.194 seconds
During ribbons ball,
x=x0+ Vt+1/2*a*(t*t)
x= 0+(15)*(3.194)+1/2*(0)* (3.194*3.194)
x= 47.9157m
So, distance (D) = 100-47.9157= 52.084m
52.084m=0+15(t)+1/2*(0)(t*t)
t=52.084/15=3.472286= 3.48seconds
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Answer:
3.1 miles
Explanation:
To solve this question it is important to remember that the distance between two mile markers is approximately 1 mile
Once this is known, the question becomes very easy to solve. We make two triangle, which have the following three points
Triangle 1: Hot-Air-Balloon, Ground, Milepost 1 - With angle of depression 20
Triangle 2: Hot-Air-Balloon, Ground, Milepost 2 - With angle of depression 18
As a reminder, the angle of depression is simply the angle the balloonist's head makes with the horizontal plane to be able to see the milepost.
From this we can simply drive two formulas using the Tan function
Equation 1 - 
Equation 2 - 
Solving them simultaneously we get the value of height (h) to be 3.0852 miles or 3.1 miles
Explanation:
It is given that,
Fundamental frequency, f = 220 Hz
(a) We know that at 0 degrees, the speed of sound in air is 331 m/s.
For open pipe, 
l is the length of pipe
Also,


(b) Let f' is the fundamental frequency of the pipe at 30 degrees and v' is its speed.


v' = 348.71 m/s
So, 

f' = 232.4 Hz
Hence, this is the required solution.