Ask question

Ask question

All categories

3 years ago

11

Some students found this information about an energy saving lamp and a filament lamp that give out almost the same amount of lig

ht.
Describe the advantages and disadvantages of each type of lamp.

1 answer:

leonid [27]3 years ago

6 0

Answer:

By replacing your home's five most frequently used light fixtures or bulbs with models that have earned the ENERGY STAR, you can save $75 each year.

Compared to traditional incandescents, energy-efficient lightbulbs such as halogen incandescents, compact fluorescent lamps (CFLs), and light emitting diodes (LEDs) have the following advantages:

Typically use about 25%-80% less energy than traditional incandescents, saving you money

Can last 3-25 times longer.

You might be interested in

Two particles are fixed to an x axis: particle 1 of charge −8.00 ✕ 10⁻⁷ C at x = 6.00 cm, and particle 2 of charge +8.00 ✕ 10⁻⁷

victus00 [196]

Answer:

0 N/C

Explanation:

Parameters given:

$q_1 = -8.00 * 10^{-7} C$

$x_1 = 6.00 cm$

$q_2 = +8.00 * 10^{-7} C$

$x_2 = 21 cm$

The distance between $q_1$ and $q_2$ is

$21 - 6 = 15cm$

Electric field is given as

$E = \frac{kq}{r^2}$

r = 15/2 = 7.5cm = 0.075m

The electric field at their midpoint due to $q_1$ is:

$E = \frac{9 * 10^9 * -8.0 * 10^{-7}}{0.075^2}$

$E_1$ = $-1.28 * 10^6 N/C$

The electric field at the midpoint due to $q_2$ is:

$E = \frac{9 * 10^9 * 8.0 * 10^{-7}}{0.075^2}$

$E_2$ = $1.28 * 10^6 N/C$

The net electric field will be:

E = $E_1$ + $E_2$

E = $-1.28 * 10^6$ + $1.28 * 10^6$

E = 0 N/C

7 0

4 years ago

An what would be needed to change an objects state of motion

VladimirAG [237]

Inertia: tendency of an object to resist changes in its velocity. An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.

~done by cessly420

mark brainliest please

hope this helped :)

8 0

4 years ago

A planet is 15 light years from earth. At which of the following speeds will the crew of a spaceship complete the trip to the pl

Svetradugi [14.3K]

Answer:

option c) 0.88c is the correct answer

Explanation:

using the Lorrentz equation we have

$t=\frac{d}{v}\sqrt{1-(\frac{v}{c})^2}$

where,

t = time taken to cover the distance

d = Distance

v = velocity

c = speed of light

given

d = 15 light years

Now,

$8years=\frac{15years\times c}{v}\sqrt{1-(\frac{v}{c})^2}$

or

$(\frac{v}{c})^2\times (\frac{8}{15})^2=1-(\frac{v}{c})^2$

or

$(\frac{v}{c})^2\times 0.284=1-(\frac{v}{c})^2$

or

$(\frac{v}{c})^2\times 0.284 + (\frac{v}{c})^2 =1$

or

$(1.284\times \frac{v}{c})^2 =1$

or

$(\frac{v}{c}) =\sqrt{\frac{1}{0.284}}$

or

$v=0.88c$

7 0

3 years ago

If we could see our own galaxy from 2 million light-years away, it would appear _________.

yaroslaw [1]

Answer:

It would appear as a flattened disk with a central bulge and spiral arms, spanning a few degrees across the sky.

Explanation:

I hope this helps! Have a great day!

Anygays-

5 0

3 years ago

I need help with one through six please

dybincka [34]

Answer:

1] 8500000 = <u>8.5 × 10⁶</u>

2] .000072 = <u>7.2 × 10⁻⁵</u>

3] 5.3 × 10⁴ = <u>53000</u>

4] 2.8 × 10⁻³ = <u>0.0028</u>

5] Velocity = $\frac{distance}{time}$

V = $\frac{50}{10}$

<u>V = 5 m/s</u>

6] Acceleration = $\frac{V1-V2}{time}$

A = $\frac{30-15}{3}$

A = $\frac{15}{3}$

<u>A = 3 m/s²</u>

7 0

2 years ago