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Alona [7]
3 years ago
9

A police car travels towards a stationary observer at a speed of 15m/s. the siren on the car emits a sound of frequency 250Hz. C

alculate the observer frequency. the speed of sound is 340m/s​
Physics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Observer Frequency = sound frequency x ( speed of sound / speed of sound - speed of car)

= 250 x (340/( 340-15))

= 261.54 Hz

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A 500 N force is applied to an object accelerating at 25 m/s^2.<br> what is the mass of the object?
krok68 [10]

Answer:

there are go fella hope u understood

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3 years ago
R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d
padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

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3 0
2 years ago
1. After a rabbit population reaches the carrying capacity of its habitat, what will most likely happen to
kifflom [539]
C) alternately increase and decrease
6 0
3 years ago
Question 6
sleet_krkn [62]

Answer:

B: Process #1: Energy is decreasing Process#2: Energy is increasing

6 0
3 years ago
You perform 556 J of work lifting a box to a height of 1.3m. How much force did you use to lift the box?
babunello [35]
The work is equal to the product between the force applied and the distance covered by the box:
W=Fd
In our problem, W=556 J, and d=1.3 m (the box is lifted to a height of 1.3 m, so it covered 1.3 m from its initial point). Therefore we can find the force applied to lift the box:
F= \frac{W}{d}= \frac{556 J}{1.3 m}=427.7 N
4 0
4 years ago
Read 2 more answers
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