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Dafna1 [17]
3 years ago
5

Given the atomic mass of select elements, calculate the molar mass of each salt. Element Molar mass (g/mol) Beryllium (Be) 9.012

Calcium (Ca) 40.08 Copper (Cu) 63.55 Palladium (Pd) 106.42 Bromine (Br) 79.90
1. The molar mass of PdBr2 is
2. The molar mass of BeBr2 is
3. The molar mass of CuBr2 is
4. The molar mass of CaBr2 is
Chemistry
1 answer:
jeka943 years ago
6 0

Answer:

1. 266.22 g/mol

2. 168.81 g/mol

3. 223.35 g/mol

4. 199.88 g/mol

Explanation:

For you to calculate the molar mass of the salt you need to sum the molar masses of every element in the salt.

In the first salt, PdBr2_{123}, the subscript 2 means that there are 2 atoms of Br. So for you to calculate the molar mass of the salt you need to sum the molar mass of Pd and 2 times the molar mass of Br, as follows:

106 g/mol + 2(79.90 g/mol) = 266.22 g/mol

In the second salt BeBr2_{123} there are 2 atoms of Br and 1 of Be, so the molar mass is:

9.012 g/mol +2(79.90 g/mol) = 186.22 g/mol

In the third salt CuBr2_{123} there are 2 atoms of Br and 1 of Cu, so the molar mass is:

63.55 g/mol + 2(79.90 g/mol) = 223.35 g/mol

And in the fourth salt CaBr2_{123} there are 2 atoms of Br and 1 of Ca, so the molar mass is:

40.08 g/mol + 2(79.90 g/mol) = 199.88 g/mol

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What is the molarity of a solution of h3po4 if 10.2 ml is neutralized by 53.5 ml of 0.20m koh what is the molarity of a solution
Anna35 [415]

The molarity of the solution of H₃PO₄ needed to neutralize the KOH solution is 0.35 M

<h3>Balanced equation </h3>

H₃PO₄ + 3KOH —> K₃PO₄ + 3H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 1
  • The mole ratio of the base, KOH (nB) = 3

<h3>How to determine the molarity of H₃PO₄ </h3>
  • Volume of acid, H₃PO₄ (Va) = 10.2 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.2 M
  • Volume of base, Ca(OH)₂ (Vb) = 53.5 mL
  • Molarity of acid, H₃PO₄ (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 10.2) / (0.2 × 53.5) = 1 / 3

(Ma × 10.2) / 10.7 = 1 / 3

Cross multiply

Ma × 10.2 × 3 = 10.7

Ma × 30.6 = 10.7

Divide both side by 30.6

Ma = 10.7 / 30.6

Ma = 0.35 M

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8 0
2 years ago
PLEASE HELP!
pogonyaev

Answer:

Q = 2.60 • 10^{3} J

Explanation:

Our specific heat capacity equation is:

Q = mC∆T

Q is the energy in joules.

m is the mass of the substance.

∆T is the temperature chance.

Let's plug in what we know.

  • We have 76.0 g of octane
  • The specific heat capacity of octane is 2.22 J/(g•K)
  • The temperature increases from 10.6º to 26.0º (a 15.4º increase)

Q = 76.0(2.22)(15.4)

Multiply.

Q = 2598.288

We want three significant figures.

Q = 2.60 • 10^{3}

or

Q = 2590 J

Hope this helps!

3 0
2 years ago
Read 2 more answers
Calculate the mass of solute in 500cm³ of 1.5mol/dm³ sodium hydroxide solution​
sineoko [7]

Answer: The general formulae for moles is n=m/mr so now we have being given to find the mass so all we have to do is to change subject

Explanation:  so we have to change subject in this question to m= n× mr . so in the question below we have being given the mole as 1.5mol/dm³  so all we have to do is to find the molecular relative mass(mr) .

to find the molecular relative mass of sodium hydroxide (NAOH) we add all of the atomic masses of all the atoms present so here we have sodium oxygen and hydrogen atoms present.

NA=23 O=16 H=1 so we add 23+16+1=40 so 40 is our molecular relative mass

now we fix it in our formulae which is m=n× mr

m=1.5× 40 =60 so our mass is 60grams or 60g

HOPE THIS HELPS!!!! if i made a mistake our MAY answer may be wrong feel free to comment

8 0
3 years ago
Please help me!!!!!!!!!!
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The coefficients should be 1; 6; 4; 4 and the coefficient of CO2 is 4
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