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muminat
3 years ago
15

If we wish to produce 35.4 moles of MgO. How many moles of O2 do we need?​

Chemistry
1 answer:
Olin [163]3 years ago
5 0
Answer : 2.5

#CarryOnLearning
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A molecular orbital is a region of space in a covalent species where electrons are likely to be found. The combination of two at
lara [203]

Answer:

bonding molecular orbital is lower in energy

antibonding molecular orbital is higher in energy

Explanation:

Electrons in bonding molecular orbitals help to hold the positively charged nuclei together, and they are always lower in energy than the original atomic orbitals.

Electrons in antibonding molecular orbitals are primarily located outside the internuclear region, leading to increased repulsions between the positively charged nuclei. They are always higher in energy than the parent atomic orbitals.

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3 years ago
Iodine 131, cesium 137, and strontium 90 are all considered isotopes. What are isotopes?
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Answer:

Isotopes are variants of an element, where the number of neutrons is different but its number of protons stay the same.

Explanation:

If the number of protons had changed then it would just be a different element.

Electron number changing simply adds charge to the atom, and doesn't change it or anything.

PLS GIVE BRAINLIEST

3 0
3 years ago
Read 2 more answers
Which of the following pH numbers are basic? (Choose 2)<br> 11<br> 5<br> 7<br> 9
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Answer:

7 is the only basic number on a pH scale

8 0
3 years ago
Molecule A is: A. Isocitrate B. Pyruvate C. Alpha-ketoglutarate D. Oxaloacete E. None of the above
hodyreva [135]

Answer:... I'm sorry.. I think you're missing something

Explanation:

3 0
3 years ago
How would you prepare 1.00 L of a 0.50 M solution of each of the following?
Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated  12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

n_1=n_2

Which can also be written in terms of concentrations and volumes:

M_1V_1=M_2V_2

Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:

V_1=\frac{M_2V_2}{M_1} \\\\V_1=\frac{1.00L*0.5M}{12M}\\ \\V_1=0.0417L=41.7mL

It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.

Best regards.

6 0
4 years ago
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