We can use the ideal gas law equation to solve for the number of moles present
PV = nRT
P - pressure - 107 kPa
V - 39.0 x 10⁻⁶ m³
n - number of moles
R - 8.314 Jmol⁻¹K⁻¹
T - temperature in K - 27 °C + 273 = 300 K
Substituting these values into the equation
107 000 Pa x 39.0 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K
n = 1.67 x 10⁻³ mol
Answer:
The molar mass of the acid is 1067.42 g/mol
Explanation:
A monotropic acid can donate one proton only in a acd base reaction thus
Monotropic acid + NaOH → NaSalt + H₂O
From the above reaction, one mole of NaOH reacts with one mole of monotropc acid
however there are 0.1578 M NaOH from 15.24 mL hence we have
Number of moles of NaOH = 0.1578 M/L × (15.24/1000) L = 0.002404872 M of NaOH
The number of moles of the monotropic acid = number of moles of NaOH = 0.0024 M. However Number of moles = mass/(molar mass)
Therefore molar mass = mass/number of moles = 2.567(2.4×10⁻³) = 1067.42 g/mol
To determine the level of radionuclides present
Answer:
1. 2Al + Cl2 = Al2Cl2
2 TiCl4 + 2Na = Ti + 2NaCl2
3. H2O2 = H2O + O2
4. Na2S + 2HCl = H2S + 2NaCl
5. Mg(OH)2 + 2HCl = MgCl2 + 2H2O
1. 3O2 = 2O3
Answer:
Transitional metals are good conductors of both heat and electricity.
But since there aren't any. It could be Calcium.
