Question

2

Answer 1

Answer:

Equation the ellipse is $\frac{x^{2}}{25}+\frac{y^{2}}{9}=1$

Step-by-step explanation:

In the question vertices of an ellipse are given as (1, 5) and (1, -5).Co vertex is (3, 0).

We know the standard form of ellipse is $\frac{x^{2} }{a^{2} } +\frac{y^{2} }{b^{2} } = 1$

If a > b then ellipse is horizontal

and the origin is (0, 0)

Given from the question a = 5 and b = 3

Since a > b therefore ellipse is horizontal

So the equation of ellipse will be

$\frac{x^{2}}{5^{2}}+\frac{y^{2}}{3^{2}}=1$

$\frac{x^{2}}{25}+\frac{y^{2}}{9}=1$

Therefore the answer is $\frac{x^{2}}{25}+\frac{y^{2}}{9}=1$