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kvasek [131]
3 years ago
15

2

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

Equation the ellipse is \frac{x^{2}}{25}+\frac{y^{2}}{9}=1

Step-by-step explanation:

In the question vertices of an ellipse are given as (1, 5) and (1, -5).Co vertex is (3, 0).

We know the standard form of ellipse is \frac{x^{2} }{a^{2} } +\frac{y^{2} }{b^{2} } = 1

If a > b then ellipse is horizontal

and the origin is (0, 0)

Given from the question a = 5 and b = 3

Since a > b therefore ellipse is horizontal

So the equation of ellipse will be

\frac{x^{2}}{5^{2}}+\frac{y^{2}}{3^{2}}=1

\frac{x^{2}}{25}+\frac{y^{2}}{9}=1

Therefore the answer is \frac{x^{2}}{25}+\frac{y^{2}}{9}=1

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