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Kazeer [188]
2 years ago
15

Which property of potential energy distinguishes it from kinetic energy?

Chemistry
1 answer:
Svet_ta [14]2 years ago
3 0
B. position.

Potential energy is associated with position.
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Which correctly lists the types of matter, in terms of their atoms, in order from least tightly packed to most tightly packed? s
SSSSS [86.1K]

Answer:

Gas, Liquid, Solid.

Explanation:

please mark brianliest :)

4 0
3 years ago
A sample of an ideal gas in a cylinder of volume 2.67 L at 298 K and 2.81 atm expands to 8.34 L by two different pathways. Path
Igoryamba

Explanation:

  • For path A, the calculation will be as follows.

As, for reversible isothermal expansion the formula is as follows.

            W = -2.303 nRT log(\frac{V_2}{V_1})

Since, we are not given the number of moles here. Therefore, we assume the number of moles, n = 1 mol.

As the given data is as follows.

              R = 8.314 J/(K mol),          T = 298 K ,

          V_{2} = 8.34 L,    V_{1} = 2.67 L

Now, putting the given values into the above formula as follows.

            W = -2.303 nRT log(\frac{V_2}{V_1})

   = -2.303 \times 1 \times 8.314 J/K mol \times 298 log(\frac{8.34}{2.67})

     = -2.303 \times 1 \times 8.314 J/K mol \times 298 \times 0.494

    = -2818.68 J

Hence, work for path A is -2818.68 J.

  • For path B, the calculation will be as follows.

Step 1: When there is no change in volume then W = 0

Hence, for step 1, W = 0

Step 2: As, the gas is allowed to expand against constant external pressure P_{external} = 1.00 atm.

So,              W = -P_{external} \times \Delta V

Now, putting the given values into the above formula as follows.

               W = -P_{external} \times \Delta V

                   = -1 atm \times (8.34 L - 2.67 L)  

                    = -5.67 atm L

As we known that, 1 atm L = 101.33 J

Hence, work will be calculated as follows.

       W = -\frac{101.33 J}{1 atm L} \times 5.67 atm L

            = -574.54 J

Therefore, total work done by path B = 0 + (-574.54 J)

                        W = -574.54 J

Hence, work for path B is -574.54 J.

3 0
3 years ago
Classify the chemical equations as being balanced or not balanced. CaO + 3C → CaC2 + CO Na + H2O → 2NaOH + H2 4Fe + O2 → 2Fe2O3
jarptica [38.1K]

Answer:

A) Balanced

B) Not Balanced

C) Not Balanced

D) Balanced

3 0
3 years ago
How many grams of CaCl₂ should be dissolved in 500.0 mL of water to make a 0.20M solution of CaCl₂?
Butoxors [25]
0.2M means 0.2mol CaCl2/1L solution.

This question didn't give us a density of the solution so needs an assumption that the solution has equal volume to water.

xmol/0.5L=0.2M
x = 0.1

0.1mol of CaCl2 is needed. Ca=40g/mol, Cl=35.5g/mol.
CaCl2 0.1mol = (40+35.5*2)*0.1=11.1g
8 0
3 years ago
On question 2 How did you get 20.8% from 48.08/10 •100?
Ilia_Sergeevich [38]

thank you sincerely for the points. you are very generous and kind to hand over these wonderful points. you went out of your way to clear the dust, shake the ground, and give me epic points. you are such a great person almost better than jorge washington himself.

3 0
2 years ago
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