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nlexa [21]
3 years ago
6

Comparing the characteristics of homogeneous and heterogeneous​

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
4 0

answer: A homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly different substances or phases.

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In your bathroom you leave the faucet dripping. If the faucet leaks 30.0 drops/minute, how much water will you waste after 3.00
Verizon [17]

First let's convert the minutes to hours (multiply minutes by 60 to get hours):

30 × 60 = 1,800 drops/hour

Now that you know how much drops there are per hour, you can multiply this answer by 3 to work out how many drops there are in 3 hours:

1,800 × 3 = 5,400 drops

We know that 5 drops is equal to 1 ml, so we can divide 5,400 by 5 to work out the amount of ml:

5,400 ÷ 5 = 1,080 ml

Therefore, your final answer is 1,080 millilitres (ml)

4 0
3 years ago
The chemical formula for sodium sulfate is Na2SO4. How many sulfur atoms are in the formula for sodium sulfate?
Gemiola [76]

Answer:

1

Explanation:

there is only one sulphur (S) atoms in the formula for sodium sulphate

5 0
2 years ago
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39 which statement about the process of dissolving is TRUE
xz_007 [3.2K]
C !!!!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
How are silicate minerals different from nonsilicate minerals
tino4ka555 [31]

Answer: The main difference between silicate minerals and nonsilicate minerals is that silicate minerals are composed of silicate groups whereas Nonsilicate minerals have no silicate groups.

Explanation:

7 0
2 years ago
A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
Romashka [77]

Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (  27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

7 0
2 years ago
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