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asambeis [7]
3 years ago
15

I'm redoing the Heat of Combustion Lab for a better grade and I REALLY need the answers and work for all questions! PLEASE!

Chemistry
1 answer:
I am Lyosha [343]3 years ago
5 0

Answer:

Hi, what are the problems on the lab?

Explanation:

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For the following reactions, write a balanced equation using half-reactions and calculate the voltage to be expected.
Iteru [2.4K]

a) 2Na(s) +2H_2O(I)→ 2Na^+(aq) + OH^-(aq)+ H_2(g)

b) 2Ag (s) +2H^(aq) → 2 Ag^+ (aq) +H_2(g)

<h3>What are half-reactions?</h3>

The half-reaction method is a way to balance redox reactions. It involves breaking the overall equation down into an oxidation part and a reduction part.

a)

2Na(s) +2H_2O(I)→ 2Na^+(aq) + OH^-(aq)+ H_2(g)

E^0 cell = E^0 (reduction)  - E^0 (oxidation)

= E^0(\frac{H_2O}{H_2}, OH^-) -E^0(Na^+/Na)

= -0.83 - (-2.71) =1.88V

b)

2Ag (s) +2H^(aq) → 2 Ag^+ (aq) +H_2(g)

E^0cell= E^0(H^+/H_2) -E^0(Ag^+/Ag)

E^0cell=-0. - (0.8) =-0.8V

Learn more about the half-reactions here:

https://brainly.in/question/18053421

#SPJ1

8 0
2 years ago
The graph below shows how the temperature and volume of a gas vary when
Sever21 [200]

Answer:

C

Explanation:

because it remains the same

3 0
3 years ago
in terms of conductivity and electronegativity, what are the characteristics in Group 2 on the periodic table?
shusha [124]
Group 2 contains soft, silver metals that are less metallic in character than group 1 elements. There is a fairly strong conductivity trend within each row, left to right, and a weaker trend top to bottom. The elements in group 2 are moderately good conductors, while the elements on the right are very poor conductors. <span>As you move vertically between rows, conductivity decreases overall, but slowly.

Group 2 have a generally low electronegativity. Electronegativity decreases moving left and down across the table.</span>
4 0
3 years ago
CHEMISTRY
andrezito [222]
Number 1.c
number 2.a
number 3.b
number 4.d
8 0
3 years ago
Read 2 more answers
Calculate the volume of each of the following gases at STP
kherson [118]
For Ar :

1 mol ------------ 22.4 L ( at STP )
7.6 mol ---------- x L 

x = 7.6 * 22.4

x = 170.24 L
-----------------------------------------------------------------
For C2H3:

1 mol ------------ 22.4 ( at STP)
0.44 mol --------- y L

y = 0.44 * 22.4

y = 9.856 L

hope this helps !.



7 0
4 years ago
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