While metallic bonds have the strong electrostatic force of attractions between the cation or atoms and the delocalized electrons in the geometrical arrangement of the two metals. ... Metallic bonds are malleable and ductile, while covalent bonds and ionic bonds non-malleable and non-ductile.
mass of N₂ = 25.76 g
mass of O₂ = 58.88 g
Explanation:
Nitrogen (N₂) will react with oxygen (O₂) to form trinitrogen tetroxide (N₂O₄).
N₂ + 2 O₂ → N₂O₄
number of moles = mass / molecular weight
number of moles of N₂O₄ = 85 / 92 = 0.92 moles
Knowing the chemical reaction we devise the following reasoning:
if 1 moles of N₂ react with 2 moles of O₂ to produce 1 mole of N₂O₄
then X moles of N₂ react with Y moles of O₂ to produce 0.92 moles of N₂O₄
X = (1 × 0.92) / 1 = 0.92 moles of N₂
Y = (2 × 0.92) / 1 = 1.84 moles of O₂
mass = number of moles × molecular weight
mass of N₂ = 0.92 × 28 = 25.76 g
mass of O₂ = 1.84 × 32 = 58.88 g
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Answer: physical
Explanation: you have not cooked them so nothing has happened
Based on the effect of temperature on a reaction, a change in temperature affects the rate constant K.
Based on the Arrhenius equation, the y-intercept gives the value of ln A.
From the value of the slope, the value of Ea is 42.1 J/mol.
<h3>What is the effect of temperature on a reaction?</h3>
A change in the temperature of a reaction acts to increase the rate of reaction.
- Change in temperature has no effect on the ideal gas constant.
- Change in temperature has no effect on the activation energy.
- Change in temperature has no effect on the concentration of reactants.
- Change is temperature can either lower or increase the rate constant of a reaction.
- Change in temperature has no effect on the order of reaction.
According to the Arrhenius equation, the y-intercept gives the value of ln A.
From the graph; slope = -Ea/R
Ea = -slope/R
Where;
- Ea is activation energy
- R is molar gas constant = 8.314 J/K.mol
- Slope = -350 K
Ea = -(-350)/8.314
Ea = 42.1 J/mol
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Answer:
200g of NaOH
Explanation:
The following data were obtained from the question:
Molar mass of NaOH = 40g/mol
Volume = 500mL
Molarity of NaOH = 10M
Next, we shall determine the number of mole of NaOH present in the solution. This is illustrated below:
Molarity of NaOH = 10M
Volume = 500mL = 500/1000 = 0.5L
Mole of NaOH =...?
Molarity = mole /Volume
10 = mole /0.5
Cross multiply
Mole = 10 x 0.5
Mole of NaOH = 5 moles
Finally, we can convert 5 moles of NaOH to grams. This is illustrated below:
Molar mass of NaOH = 40g/mol
Mole of NaOH = 5 moles
Mass of NaOH =...?
Mole = Mass /Molar Mass
5 = Mass /40
Cross multiply
Mass = 5 x 40
Mass of NaOH = 200g
Therefore, 200g of NaOH is needed to prepare the solution.
