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Keith_Richards [23]
3 years ago
9

How many milliliters of calcium, with a density of 1.55 g/mL, are needed to produce 98.5 grams of calcium hydroxide in the singl

e-replacement reaction below? Show all steps of your calculation as well as the final answer. Ca + H2O → Ca(OH) 2 + H2
Chemistry
1 answer:
Nana76 [90]3 years ago
7 0
Answer is: 34,35 mL.
Reaction: Ca + 2H₂O → Ca(OH)₂ + H₂
m(Ca(OH)₂) = 98,5g.
n(Ca(OH)₂) = m÷M = 98,5g÷74g/mol = 1,33mol.
From reaction: n(Ca):n(Ca(OH)₂) = 1:1.
n(Ca) = n(Ca(OH)₂) = 1,33mol.
m(Ca) = n(Ca)·M(Ca) = 1,33mol·40g/mol = 53,24g.
d(Ca) = <span>1.55 g/mL.
V(Ca) = m(Ca)</span>÷d(Ca) = <span>53,24g</span>÷1.55 g/mL = 34,35 mL.
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Answer : The original concentration of copper (II) sulfate in the sample is, 5.6\times 10^{-1}g/L

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Number of moles of Cu = Number of moles of CuSO_4

Number of moles of CuSO_4 = 1.40\times 10^{-3}mole

Now we have to calculate the molarity of CuSO_4

\text{Molarity}=\frac{\text{Moles of }CuSO_4\times 1000}{\text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{1.40\times 10^{-3}mole\times 1000}{400.mL}=0.0035M

To change mol/L into g/L, we need to multiply it with molar mass of CuSO_4

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Concentration in g/L = 0.0035M\times 159.609g/mol=0.5586g/L\approx 5.6\times 10^{-1}g/L

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From the image shown, the uncertainty in the weighing balance extends to the hundredth place.

<h3>What is a balance?</h3>

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Looking at the image shown, the following are true;

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Learn more about weighing balance: brainly.com/question/8902159

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