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Keith_Richards [23]
3 years ago
9

How many milliliters of calcium, with a density of 1.55 g/mL, are needed to produce 98.5 grams of calcium hydroxide in the singl

e-replacement reaction below? Show all steps of your calculation as well as the final answer. Ca + H2O → Ca(OH) 2 + H2
Chemistry
1 answer:
Nana76 [90]3 years ago
7 0
Answer is: 34,35 mL.
Reaction: Ca + 2H₂O → Ca(OH)₂ + H₂
m(Ca(OH)₂) = 98,5g.
n(Ca(OH)₂) = m÷M = 98,5g÷74g/mol = 1,33mol.
From reaction: n(Ca):n(Ca(OH)₂) = 1:1.
n(Ca) = n(Ca(OH)₂) = 1,33mol.
m(Ca) = n(Ca)·M(Ca) = 1,33mol·40g/mol = 53,24g.
d(Ca) = <span>1.55 g/mL.
V(Ca) = m(Ca)</span>÷d(Ca) = <span>53,24g</span>÷1.55 g/mL = 34,35 mL.
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Explanation:

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As you can see in the figure, each phosphorus atom is bonded to the other three atoms.A bond is formed when two atoms share one electron each and the pair is called bonding pair.

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