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alexandr402 [8]
3 years ago
5

A rocket with a mass of 2.0 Ã 106 kg is designed to take off from the surface of the earth by burning fuel and ejecting it with

an exhaust speed of 3500 m/s. what is the minimum rate at which the fuel should be consumed in order to attain liftoff?
Physics
1 answer:
julsineya [31]3 years ago
6 0

thrust force getting from the burning of mass should balance the weight of the rocket

here thrust force is given as

F_t = v\frac{dm}{dt}

now by force balance we can say

mg = v \frac{dm}{dt}

now plug in all values in this

(2 \times 10^6)(9.8) = 3500 \times \frac{dm}{dt}

\frac{dm}{dt} = \frac{19.6 \times 10^6}{3500}

\frac{dm}{dt} = 5600 kg/s

so rate of mass burning per second will be 5600 kg per second in order to lift up the rocket

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Second question (middle left):
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