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Iteru [2.4K]
2 years ago
9

Ramu,the gardener,is trying to pull out weeds. however,he has to apply great force.why do you think he has to apply to much forc

e?
Physics
1 answer:
jasenka [17]2 years ago
4 0

Answer:

Roots are basically hooked into the ground?

Explanation:

Maybe you could comment here the choices if it's multiple choice.

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The International Space Station (ISS) orbits Earth at an altitude of 4.08 × 105 m above the surface of the planet. At what veloc
alukav5142 [94]

This question involves the concepts of orbital velocity and orbital radius.

The orbital velocity of ISS must be "7660.25 m/s".

The orbital velocity of the ISS can be given by the following formula:

v=\sqrt{\frac{GM}{R}}

where,

v = orbital velocity = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of Earth = 5.97 x 10²⁴ kg

R = orbital radius = radius of earth + altitude = 63.78 x 10⁵ m + 4.08 x 10⁵ m

R = 67.86 x 10⁵ m

Therefore,

v=\sqrt{\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{67.86\ x\ 10^5\ m}}

<u>v = 7660.25 m/s</u>

Learn more about orbital velocity here:

brainly.com/question/541239

3 0
2 years ago
A force of 16 N to the west is applied to each object below. Which object will
Montano1993 [528]

41kg object that is moving east at 5 m s

7 0
2 years ago
Read 2 more answers
If the force squeezing two surfaces together is decreased, the force of dry sliding friction between the two surfaces will most
Anastasy [175]

<em>If the force squeezing two surfaces together is decreased, the force of dry sliding friction between the two surfaces will most likely decrease. </em>

<u>therefore your answer is B)</u><u>d</u><u>e</u><u>crease </u>

Hope this helps you- have a good day bro cya)

7 0
2 years ago
Mountains are part of which earth sphere?? Am I correct?
sammy [17]
You are correct. Mountains are part of the lithosphere.
8 0
3 years ago
Read 2 more answers
During a braking test, a car is brought to rest beginning from an initial speed of 60 mi/hr in a distance of 120 ft. With the sa
maw [93]

Answer:

Explanation:

Given

Initial speed u=60\ mi/hr\approx 88\ ft/s

distance traveled before coming to rest d_1=120\ ft

using equation of motion

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

0-(88)^2=2\times a\times 120---1

for u_2=80\ mi/hr\approx 117.33\ ft/s

using same relation we get

0-(117.33)^2=2\times a\times (d_2)----2

divide 1 and 2 we get

(\frac{88}{117.33})^2=\frac{120}{d_2}

d_2=213.32\ ft

So a distance if 213.32 ft is required to stop the vehicle with 80 mph speed

8 0
3 years ago
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