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slega [8]
3 years ago
7

A decrease in the height of a column in a mercury barometer means that _____. air pressure is increasing wind speed is increasin

g air pressure is decreasing air pressure is being deflected by the coriolis effect
Physics
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

Correct answer is  air pressure is decreasing

Explanation:

Atmospheric pressure is usually measured with the help of  barometer. A barometer consist of  a glass tube in which there is a column of mercury. This column of mercury changes with the changing weight of the atmosphere. It means height of mercury column depend on air pressure.Height of  height of a column in a mercury barometer is directly proportional to atmospheric pressure.Therefore a decrease in the height of a column in a mercury barometer means that air pressure is decreasing.

Lady_Fox [76]3 years ago
3 0
I think it's "air pressure is decreasing".
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Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod
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As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

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Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w
mario62 [17]

Answer:

The distance we need to walk in other not to hear the speakers for a speaker separation distance of 1 m, while walking in front of one of the speaker is 1.875 meters

Explanation:

The wavelength of the wave is obtained from the formula, v = f × λ

Where;

v = The velocity of the wave = 344 m/s

f = The frequency of the wave = 688 Hz

λ = The wavelength of the wave

λ = v/f = (344 m/s)/(688 Hz) = 1/2 meters

Therefore, for one not to be able to here the speakers, there must be destructive interference and R₁ - R₂ = λ/2 = (1/2)/2 = 1/4 m

Where R₁ and R₂ are the distances from the person to the two speakers respectively

When the distance between the two speakers = 1 meter, we have

R₁ = √(x² + d²), R₂ = √((1 - x)² + d²)

R₁ - R₂ = √(x² + d²) - √((1 - x)² + d²) = 1/4

When we walk from directly in front of one of the speakers, we get;

R₁ - R₂ = √(1 + d²) - √((1 - 1)² + d²) = 1/4

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√(1² + d²)  = 1/4 + d

Square both sides gives

1² + d² = 1/16 + d/2 + d²

1²  = 1/16 + d/2

d/2 = 1 - 1/16 = 15/16

d = 2 × 15/16 = 15/8

d = 15/8 = 1.875 meters.

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