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slega [8]
3 years ago
7

A decrease in the height of a column in a mercury barometer means that _____. air pressure is increasing wind speed is increasin

g air pressure is decreasing air pressure is being deflected by the coriolis effect
Physics
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

Correct answer is  air pressure is decreasing

Explanation:

Atmospheric pressure is usually measured with the help of  barometer. A barometer consist of  a glass tube in which there is a column of mercury. This column of mercury changes with the changing weight of the atmosphere. It means height of mercury column depend on air pressure.Height of  height of a column in a mercury barometer is directly proportional to atmospheric pressure.Therefore a decrease in the height of a column in a mercury barometer means that air pressure is decreasing.

Lady_Fox [76]3 years ago
3 0
I think it's "air pressure is decreasing".
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What is velocity and it’s SI Unit?
svp [43]

Answer:

Velocity is the displacement (change In position of an an object it is similar to distance ) divided by the time taken. SI unit m/s (metre per second)

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3 years ago
A car of mass 1,000 kilograms is moving initially at the speed of 22 meters/second. When the brakes are applied, it takes the ca
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i believe it is C....tell me if im right please<3

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3 years ago
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Calculate the Energy (E) in joules for that wavelength and record it in the table below. Remember that E = HF, where h the Planc
Viefleur [7K]

In that formula for Energy, 'F' is the frequency of the photon.
But <u>Frequency = (speed)/(wavelength)</u>, so we can write the
Energy formula as
                                 E = h c / (wavelength) .

So the energy, in joules, of a photon with that wavelength, is . . .

                                 E = (6.6 x 10⁻³⁴) x (3 x10⁸) / (that wavelength)

                                    = <em>(1.989 x 10⁻²⁵) / (that wavelength, in meters) .</em>


5 0
3 years ago
Two electric charges qa = 1. 0 μc and qb = - 2. 0 μc are located 0. 50 m apart. how much work is needed to move the charges apar
melisa1 [442]

The total work done of 0.018 joules is needed to move the charges apart and double the distance between them.

We have two electric charges q(A) = 1μc and q(B) = -2μc kept at a distance 0.5 meter apart.

We have to calculate  much work is needed to move the charges apart and double the distance between them.

<h3>What s the formula to calculate the Potential Energy of a system of two charges (say 'q' and 'Q') separated by a distance 'r' ?</h3>

The potential energy of the system of two charges separated by a distance is given by -

U = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}

In order to solve this question, it is important to remember the work - energy theorem which states -

"The change in the energy of the body is equal to work done on it"

Hence, using this work -energy theorem in the question given to us we get -

U_{f} -U_{i} =W_{net}

In our case -

U_{f}  = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r}\\\\U_{i} =   \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W=\frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r} - \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W = \frac{qQ}{4\pi\epsilon_{o}r} (\frac{1}{2} -1)\\\\W = 9\times 10^{9}\times \frac{1 \times 10^{-6} \times 2\times10^{-6} }{0.5} \times \frac{-1}{2}

W = 0.018 joules

Hence, the total work done should be 0.018 joules.

To solve more question on potential energy, visit the link below -

brainly.com/question/15014856

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4 0
2 years ago
A solenoid is built with 870 turns uniformly distributed over a length of 0.390 m to produce a magnetic field of magnitude 1.00
Y_Kistochka [10]

Answer:

35.7 mA

Explanation:

The magnetic field inside a solenoid is given by:

B=\mu_0 I n (1)

where

\mu_0 = 4\pi \cdot 10^{-7} H/m is the vacuum permeability

I is the current

n is the number of turns per unit length

Since we have

N = 870 turns

L = 0.390 (length of the solenoid)

we can calculate n

n=\frac{N}{L}=\frac{870}{0.390}=2230.8

And now we can re-arrange eq.(1) to find the current, I:

I=\frac{B}{\mu_0 n}=\frac{1.00\cdot 10^{-4} T}{(4\pi\cdot 10^{-7} H/m)(2230.8m^{-1})}=0.0357 A = 35.7 mA

6 0
3 years ago
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