Which statement accurately describes impulse?<br> State corrrect ans

which pole of a compass needle points north ? please give simple answer with little explaining if any :)

Mumz [18]

I think the North Pole
If I understand this correctly

6 0

3 years ago

A small rocket to gather weather data is launched straight up. Several seconds into the flight, its velocity is 120 mis and it i

padilas [110]

The net force on the rocket is 864 N

Explanation:

The net force acting on the rocket can be calculated by using Newton's second law of motion, which states that:

F = ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the rocket in this problem, at a certain instant we have:

m = 48 kg

$a=18 m/s^2$

Therefore, the force on the rocket is

$F=(48)(18)=864 N$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0

3 years ago

A 0.80-μm-diameter oil droplet is observed between two parallel electrodes spaced 11 mm apart. The droplet hangs motionless if t

Arisa [49]

A) $2.4\cdot 10^{-16}kg$

The radius of the oil droplet is half of its diameter:

$r=\frac{d}{2}=\frac{0.80 \mu m}{2}=0.40 \mu m = 0.4\cdot 10^{-6}m$

Assuming the droplet is spherical, its volume is given by

$V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (0.4\cdot 10^{-6} m)^3=2.68\cdot 10^{-19} m^3$

The density of the droplet is

$\rho=885 kg/m^3$

Therefore, the mass of the droplet is equal to the product between volume and density:

$m=\rho V=(885 kg/m^3)(2.68\cdot 10^{-19} m^3)=2.4\cdot 10^{-16}kg$

B) $1.5\cdot 10^{-18}C$

The potential difference across the electrodes is

$V=17.8 V$

and the distance between the plates is

$d=11 mm=0.011 m$

So the electric field between the electrodes is

$E=\frac{V}{d}=\frac{17.8 V}{0.011 m}=1618.2 V/m$

The droplet hangs motionless between the electrodes if the electric force on it is equal to the weight of the droplet:

$qE=mg$

So, from this equation, we can find the charge of the droplet:

$q=\frac{mg}{E}=\frac{(2.4\cdot 10^{-16}kg)(9.81 m/s^2)}{1618.2 V/m}=1.5\cdot 10^{-18}C$

C) Surplus of 9 electrons

The droplet is hanging near the upper electrode, which is positive: since unlike charges attract each other, the droplet must be negatively charged. So the real charge on the droplet is

$q=-1.5\cdot 10^{-18}C$

we can think this charge has made of N excess electrons, so the net charge is given by

$q=Ne$

where

$e=-1.6\cdot 10^{-19}C$ is the charge of each electron

Re-arranging the equation for N, we find:

$N=\frac{q}{e}=\frac{-1.5\cdot 10^{-18}C}{-1.6\cdot 10^{-19}C}=9.4 \sim 9$

so, a surplus of 9 electrons.

3 0

3 years ago

which words are readable red word on white paper in red light or blue words on white paper in blue light

Angelina_Jolie [31]

Answer:

second

Explanation:

the first let's everything appear red, the send would produce black(-ish) words on paper that's appealing blue

6 0

3 years ago

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A box of mass 12 kg is at rest on a flat floor. The coefficient of static friction between the box and floor is 0.42. What is th

Oxana [17]

The maximum static force that can be applied is equal to the normal force*the frictional force. the normal force on the box is equal to mg since the floor is flat using 9.81m/s^2 for gravity 12kg*9.81m/s^2 = 118N multiplying the normal force by the frictional force you get a 118*.42= 49.6N so overcome the force of static friction on the box a minimum of 49.6N would need to be applied.

5 0

3 years ago

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Which statement accurately describes impulse? State corrrect ans