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Anit [1.1K]
2 years ago
5

If you are in a car and your sibling is driving in the same car next to you at the same speed, does your brother appear to be mo

ving?
Physics
1 answer:
VLD [36.1K]2 years ago
7 0

Answer:

yes, because you guy's are moving in a car. because if you think about it, your parents are driving, but the cars moving so basically you guys would be moving.

please mark as brainly

You might be interested in
Will give brainliest!
tamaranim1 [39]
Howdy!!

your answer is ----


total resistance 1/R = 1/9+1/9+1/9
= 3/9

=> R = 9/3 = 3 ohm
according to ohms law

voltage = current × resistance

= 4 × 3 = 12 volt


hope it help you
8 0
3 years ago
What is most likely to happen during deposition?
Iteru [2.4K]

Answer:

a person appears at a specified time and place and gives sworn testimony

Explanation:

Hope this helps

6 0
2 years ago
A merry-go-round with a a radius of R = 1.63 m and moment of inertia I = 196 kg-m2 is spinning with an initial angular speed of
Ulleksa [173]

Answer:

299.88 kgm²/s

499.758 kgm²/s

Explanation:

R = Radius of merry-go-round = 1.63 m

I = Moment of inertia = 196 kgm²

\omega_i = Initial angular velocity = 1.53 rad/s

m = Mass of person = 73 kg

v = Velocity = 4.2 m/s

Initial angular momentum is given by

L=I\omega_i\\\Rightarrow L=196\times 1.53\\\Rightarrow L=299.88\ kgm^2/s

The initial angular momentum of the merry-go-round is 299.88 kgm²/s

Angular momentum is given by

L=mvR\\\Rightarrow L=73\times 4.2\times 1.63\\\Rightarrow L=499.758\ kgm^2/s

The angular momentum of the person 2 meters before she jumps on the merry-go-round is 499.758 kgm²/s

5 0
3 years ago
A 15.0 kg crate, initially at rest, slides down a ramp 2.0 m long and inclined at an angle of 20.0° with the horizontal. Using t
Elis [28]

The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of

<em>F</em> = <em>mg</em> sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N

Then the work done by this force on the crate as it slides down the ramp is

<em>W</em> = <em>F d</em> = (50.3 N) (2.0 m) ≈ 101 J

The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so

<em>W</em> = <em>K</em> = 1/2 <em>mv</em> ^2

Solve for <em>v</em> :

<em>v</em> = √(2<em>W</em>/<em>m</em>) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s

3 0
3 years ago
A wave is traveling at a speed of 12m/s and its wavelength is 3 m calculate the wave frequency
White raven [17]

Answer:

f = 4 Hz

Explanation:

Given that,

The speed of a wave, v = 12 m/s

The wavelength of a wave, \lambda=3\ m

We need to find the frequency of the wave. We know that the speed of wave is equal to the product of wavelength and frequency. So,

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{12}{3}\\\\f=4\ Hz

So, the frequency of the wave is equal to 4 Hz.

6 0
2 years ago
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