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Artist 52 [7]
2 years ago
6

Which has a higher acceleration: a 10 kg object acted upon with a net force of 20 N or an 18 kg object acted on by a net force o

f 30 N
Physics
1 answer:
Bingel [31]2 years ago
7 0
When a force F is acting on an object of mass m, the acceleration of the object is (Newton's second law)
a= \frac{F}{m}
The first object has a mass of 10 kg and a force of 20 N is acting on it, so its acceleration is
a_1= \frac{20 N}{10 kg}=2 m/s^2
The second object has a mass of 18 kg and a force of 30 N is acting on it, so its acceleration is
a_2= \frac{30 N}{18 kg}=1.67 m/s^2
So, the first object has higher acceleration.
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An object travels in a circular path of radius 5.0 meters at a uniform speed of 10. m/s. What is the magnitude of the object's a
vladimir1956 [14]
I think F= mv²/r
And F=ma
So, ma = mv²/r
a = v²/r
a = 100/5
a = 20 m/s
8 0
3 years ago
Read 2 more answers
A baseball travels 200 metes in 6 seconds, what is the baseball’s velocity?
goldenfox [79]

Answer:

33.33 m/sec

Explanation:

A baseball travels 200 metes in 6 seconds,

what is the baseball’s velocity?

use the formula: velocity = distance over time

where (d) distance = 200 m

and (t) time = 6 sec.

plugin values into the formula:

v = d / t

  = 200 m / 6 sec

  = 33.33 m/sec.

therefore, the baseball's velocity is 33.33 m/sec

8 0
3 years ago
According to the Heisenberg uncertainty principle, if the uncertainty in the speed of an electron is 3.5 × 103 m/s, the uncertai
GREYUIT [131]

Explanation:

It is given that,

Uncertainty in the speed of an electron, \Delta v=3.5\times 10^3\ m/s

According to Heisenberg uncertainty principle,

\Delta x.\Delta p=\dfrac{h}{4\pi}

\Delta x is the uncertainty in the position of an electron

Since, \Delta p=m\Delta v

\Delta x=\dfrac{h}{4\pi.m \Delta v}

\Delta x=\dfrac{6.6\times 10^{-34}}{4\pi\times 9.1\times 10^{-31}\times 3.5\times 10^3}

\Delta x=1.64\times 10^{-8}\ m

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6 0
3 years ago
24 POINTS!!!!!!!!!!!!!!!
TEA [102]
Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880

Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000

Lost Energy = 5880 - 3000 = 2880 J

In short, Your Answer would be 2880 Joules

Hope this helps!
7 0
2 years ago
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Yakvenalex [24]
Displacement = (distance between start and end points) in the direction of (direction from start to end point). Distance = (11.3-3.38)= 7.92 m. Direction = the negative 'x' direction.
5 0
3 years ago
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