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Artist 52 [7]
2 years ago
6

Which has a higher acceleration: a 10 kg object acted upon with a net force of 20 N or an 18 kg object acted on by a net force o

f 30 N
Physics
1 answer:
Bingel [31]2 years ago
7 0
When a force F is acting on an object of mass m, the acceleration of the object is (Newton's second law)
a= \frac{F}{m}
The first object has a mass of 10 kg and a force of 20 N is acting on it, so its acceleration is
a_1= \frac{20 N}{10 kg}=2 m/s^2
The second object has a mass of 18 kg and a force of 30 N is acting on it, so its acceleration is
a_2= \frac{30 N}{18 kg}=1.67 m/s^2
So, the first object has higher acceleration.
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An object is floating in equilibrium on the surface of a liquid. The object is then removed and placed in another container, fil
Anestetic [448]

Answer:

The fraction of its volume inside liquid  is increased .

Explanation:

According to principle pf floatation , an object floats on the surface of water

when the weight of  liquid displaced by it becomes equal to weight of the object . weight of the liquid depends upon the density of the liquid .

In the second case , when the body is dipped into liquid of lesser density , in order to balance the weight of body , more volume of liquid will be displaced so that weight of displaced liquid becomes equal to object's weight . So the body floats with greater depth inside liquid . The fraction of its volume inside liquid  is increased .

4 0
2 years ago
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barxatty [35]
I think this is the solution:

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2: Na-6, Mo-1, O-4
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6: Ge- 15, N-4
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8: H-7, F-1
9: N-1, O-5, H-1, S-1
10: H-8
11: Nb-1, O-1, C-1, I-3
12: C-3, F-3, S-1, O-3, H-1
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5 0
2 years ago
We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
frez [133]

We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

F_D = c_D A \frac{\rho V^2}{2}

Where,

F_D = Drag Force

c_D = Drag coefficient

A = Area

\rho= Density

V = Velocity

Our values are given by,

c_D = 0.5 (That is proper of a cone-shape)

A = 9m^2

\rho = 1.2Kg/m^3

V = 6.5m/s

Part A ) Replacing our values,

F_D = 0.5*9*\frac{1.2*6.5^2}{2}

F_D = 114.075N

Part B ) To find the torque we apply the equation as follow,

\tau = F*d

\tau = (114.075N)(7)

\tau = 798.525N.m

3 0
3 years ago
Express the kinetic energy K in terms of the potential energy U.<br><br><br> K=GMm/2R
max2010maxim [7]

Answer:

K = -½U

Explanation:

From Newton's law of gravitation, the formula for gravitational potential energy is;

U = -GMm/R

Where,

G is gravitational constant

M and m are the two masses exerting the forces

R is the distance between the two objects

Now, in the question, we are given that kinetic energy is;

K = GMm/2R

Re-rranging, we have;

K = ½(GMm/R)

Comparing the equation of kinetic energy to that of potential energy, we can derive that gravitational kinetic energy can be expressed in terms of potential energy as;

K = -½U

7 0
3 years ago
What are the primary colors? What are the secondary colors?
Jet001 [13]

Color Basics

Three Primary Colors (Ps): Red, Yellow, Blue.

Three Secondary Colors (S'): Orange, Green, Violet

5 0
2 years ago
Read 2 more answers
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