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Artist 52 [7]
3 years ago
6

Which has a higher acceleration: a 10 kg object acted upon with a net force of 20 N or an 18 kg object acted on by a net force o

f 30 N
Physics
1 answer:
Bingel [31]3 years ago
7 0
When a force F is acting on an object of mass m, the acceleration of the object is (Newton's second law)
a= \frac{F}{m}
The first object has a mass of 10 kg and a force of 20 N is acting on it, so its acceleration is
a_1= \frac{20 N}{10 kg}=2 m/s^2
The second object has a mass of 18 kg and a force of 30 N is acting on it, so its acceleration is
a_2= \frac{30 N}{18 kg}=1.67 m/s^2
So, the first object has higher acceleration.
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A ball is thrown vertically upward with a speed of 19.0 m/s. (a) How high does it rise? m (b) How long does it take to reach its
Arte-miy333 [17]

Answer with Explanation:

We are given that

Initial speed=u=19 m/s

a.g=9.8m/s^2

Final velocity of ball=v=0

v=u-gt

g is negative because the ball is going against to gravity.

0=19-9.8t

9.8t=19

t=\frac{19}{9.8}=1.94 s

s=ut-\frac{1}{2}gt^2

Using the formula

s=19(1.94)-\frac{1}{2}(9.8)(1.94)^2

s=18.4 m

a.The ball rise upto height 18.4 m

b.It take 1.94 s to reach its highest point.

c.Initial velocity=0,s=18.4 m

s=ut+\frac{1}{2}gt^2

18.4=0(t)+\frac{1}{2}(9.8)t^2

18.4=4.9t^2

t^2=\frac{18.4}{4.9}

t=\sqrt{\frac{18.4}{4.9}}

t=1.94 s

v=u+gt

Using the formula

v=0+9.8(1.94)=19 m/s

7 0
4 years ago
Read 2 more answers
One example of a physical change is
ycow [4]

Answer:

Mixing a milkshake

Explanation:

Becuse it’s physics becuse your using muscle and moving it and changing it by force.

7 0
3 years ago
Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate
maria [59]

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

       The length of the track is l =  1.0 \ km  =  1000 \  m

       The speed of  A is  v__{A}} =  20 \ m/s

       The uniform acceleration of  B is  a__{B}} =  0.333 \ m/s^2

  Generally the time taken by go-cart  A is mathematically represented as

              t__{A}} = \frac{l}{v__{A}}}

=>          t__{A}} = \frac{1000}{20}

=>           t__{A}} =  50 \  s

  Generally from kinematic equation we can evaluate the time taken by go-cart B as

             l =  ut__{B}} + \frac{1}{2}  a__{B}} * t__{B}}^2

given that go-cart B starts from rest  u =  0 m/s

So

            1000 =  0 *t__{B}} + \frac{1}{2}  * 0.333  * t__{B}}^2

=>         1000 =  0 *t__{B}} + \frac{1}{2}  0.333  * t__{B}}^2            

=>         t__{B}} =  77.5 \  seconds  

 

Comparing  t__{A}} \  and  \ t__{B}}  we see that t__{A}} is smaller so go-cart A is  faster

   

       

3 0
3 years ago
A skateboarder who travels 60 meters in 30 seconds has a speed of
natulia [17]

2m/s

Explanation:

Given parameters:

Distance traveled = 60m

time taken = 30seconds

Unknown:

Speed of skateboarder = ?

Solution:

Speed is the rate of change of distance with time taken. It is a scalar quantity that only revers magnitude;

    Speed = \frac{distance}{time}

    Speed = \frac{60}{30} = 2m/s

learn more:

Speed brainly.com/question/1548911

#learnwithBrainly

4 0
3 years ago
What happens when the voltage increases and the resistance stays the same in a electrical circuit?
Orlov [11]

Answer:

The current in the circuit increases

Explanation:

The ohm's law states that the potential across a circuit is proportional to the current in the circuit.

                                             V ∝ I

Where 'V' is the potential difference across the circuit and 'I' is the current in the circuit.

The proportionality constant present in the equation is the resistance of the circuit. Hence, the equation becomes

                                             V = IR

According to the equation, when V is directly proportional to 'I' where 'R' remains as constant, then the change in 'V is brings change in 'I' to make the equation valid.

So, when there is an increase in the voltage, the current on the circuit increases.

4 0
3 years ago
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