Answer : diffraction
Explanation : Diffraction is the phenomenon of bending of sound waves around the small openings or obstacles.
Tierra is playing in her backyard when she hears her friend calling out to her. Tierra can hear her friend even when she can't see her. This is because the sound is spreading out from the small openings and hence diffraction of sound wave occurs.
The distance traveled by the box over the first 4 s is 16 m.
To solve the problem above, First, we apply newton's Fundamental equation of force.
<h3 /><h3>Newton's fundamental equation of force:</h3>
F = ma...................... Equation 1
Where
- F = Force
- m = mass of the box
- a = acceleration
make "a " the subject of the equation
a = F/m...................... Equation 2
From the question,
Given:
Substitute these values into equation 2
a = 10/5
a = 2 m/s²
Finally, we use the equation of motion to calculate the distance it will travel over the given period of time.
<h3><u>Equation of motion</u></h3>
s = ut+at²/2........................... Equation 3
Where:
- s = total distance traveled
- t = time
- u = initial velocity
Given:
- t = 4 s
- u = 0 m/s (at rest)
Substitute these values into equation 3
- s = 0(4)+(2×4²)/2
- s = 0+32/2
- s = 16 m
Hence, the distance traveled by the box over the first 4 s is 16 m
Learn more about Newton's fundamental equation here: brainly.com/question/13370981
Answer:
1) Recollapsing universe
2) critical universe
3) Coasting universe
Explanation:
According to the smallest ration (ratio actual mass density to current density) to largest ration, rank of models for expansion of universe are
1) Recollapsing universe -in this, metric expansion of space is reverse and universe recollapses.
2) critical universe - in this, expansion of universe is very low.
3) Coasting universe - in this, expansion of universe is steady and uniform
Answer:
T = 3.475 s
Time period is independent from mass
Explanation:
- To reduce the human error in taking any measurements we take multiple N number of readings. Then sum up all the readings and divide by N to find an average. The error between each individual reading and the actual reading is reduced by repetition.
- We use the plot of T^2 against L to form a linear relationship between two variables. We square the entire the equation for linearize the equation.
- Given, L = 3 m . The time period is approximated by a pendulum expression given as:
T = 2*pi*sqrt ( L / g )
Where, g is the gravitational acceleration 9.81 m/s^2
- Then we have:
T = 2*pi*sqrt ( 3 / 9.81 )
T = 3.475 s
- From above expression we see that time period is independent from the mass at the end of the string but a function of pendulum geometry and kinetics.
Answer:
The value of heat transfer during the process Q = - 29.49 KJ
Explanation:
Given data
= 50 
= 344.7 k pa
= 0.113 
F = 366.4 K
= 477.6 K
Poly tropic index n = 1.2
gas constant for oxygen = 0.26 
From ideal gas equation
= m R 
Put all the values in above equation we get
⇒ 344.7 × 0.113 = m × 0.26 × 366.4
⇒ m = 0.408 kg
Heat transfer in poly tropic process is given by
Q = ![\frac{\gamma - n}{( \gamma - 1)( n - 1)} [ {m R (T_{1} - T_{2} ) ]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cgamma%20-%20n%7D%7B%28%20%5Cgamma%20-%201%29%28%20n%20-%201%29%7D%20%5B%20%7Bm%20R%20%28T_%7B1%7D%20-%20T_%7B2%7D%20%20%29%20%5D)
Put all the values in above formula we get
⇒ Q = ![\frac{1.4 - 1.2}{( 1.4 - 1)( 1.2 - 1)} [ {m R (T_{1} - T_{2} ) ]](https://tex.z-dn.net/?f=%5Cfrac%7B1.4%20-%201.2%7D%7B%28%201.4%20-%201%29%28%201.2%20-%201%29%7D%20%5B%20%7Bm%20R%20%28T_%7B1%7D%20-%20T_%7B2%7D%20%20%29%20%5D)
⇒ Q = 2.5 × 0.408 × 0.26 × ( 366.4 - 477.6 )
⇒ Q = - 29.49 KJ
This is the value of heat transfer during the process & negative sign shows that heat is lost during the process.
