Question

A falling object accelerates from -10.0 m/s to -30.0 m/s. how much time does it take?

Answer 1

Answer:

2.04 s

Explanation:

v = at + v₀

(-30.0 m/s) = (-9.8 m/s²) t + (-10.0 m/s)

t = 2.04 s

Answer 2

Answer:

The time taken by the falling object is 2.04 sec

Solution:

The initial velocity $V = -10 m/s$

The final velocity $V_1 = -30m/s$

Let us assume that the time taken is t sec

We know that the acceleration due to gravity $g = 9.8m/sec^2$

As per the free falling object motion,

$V_1 = V -gt$

$-30 = -10 -9.8\times t$

$-30+10 = -9.8\times t$

$-20 = -9.8\times t$

$t =\frac{20}{9.8} = 2.04$

So, it takes total 2.04 sec