A falling object accelerates from -10.0 m/s to -30.0 m/s. how much time does it take?

Physics

2 answers:

Zepler [3.9K]3 years ago

8 0

Answer:

2.04 s

Explanation:

v = at + v₀

(-30.0 m/s) = (-9.8 m/s²) t + (-10.0 m/s)

t = 2.04 s

KIM [24]3 years ago

8 0

Answer:

The time taken by the falling object is 2.04 sec

Solution:

The initial velocity $V = -10 m/s$

The final velocity $V_1 = -30m/s$

Let us assume that the time taken is t sec

We know that the acceleration due to gravity $g = 9.8m/sec^2$

As per the free falling object motion,

$V_1 = V -gt$

$-30 = -10 -9.8\times t$

$-30+10 = -9.8\times t$

$-20 = -9.8\times t$

$t =\frac{20}{9.8} = 2.04$

So, it takes total 2.04 sec

You might be interested in

the object on the right gained mass so that it had as much mass as the object on the left, how would the gravitational force bet

kherson [118]

The gravitational force between the objects A. It would increase.

Explanation:

The magnitude of the gravitational force between two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where

G is the gravitational constant

$m_1,m_2$ are the masses of the two objects

r is the separation between the objects

In this problem, we are told that one of the object (the one on the right) gains mass: this means that, for instance, the value of $m_2$ increases. We can see from the equation that the gravitational force is directly proportional to the masses: therefore, if one of the masses increases (while the distance between the two objects remains constant), it means that the force also increases.