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steposvetlana [31]
3 years ago
14

A falling object accelerates from -10.0 m/s to -30.0 m/s. how much time does it take?

Physics
2 answers:
Zepler [3.9K]3 years ago
8 0

Answer:

2.04 s

Explanation:

v = at + v₀

(-30.0 m/s) = (-9.8 m/s²) t + (-10.0 m/s)

t = 2.04 s

KIM [24]3 years ago
8 0

<u>Answer</u>:

The time taken by the falling object is 2.04 sec

<u>Solution:</u>

The initial velocity V = -10 m/s

The final velocity V_1 = -30m/s

Let us assume that the time taken is t sec

We know that the acceleration due to gravity g = 9.8m/sec^2

As per the free falling object motion,

V_1 = V -gt

-30 = -10 -9.8\times t

-30+10 = -9.8\times t

-20 = -9.8\times t

t =\frac{20}{9.8} = 2.04

So, it takes total 2.04 sec

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