2 years ago

A cylinder-piston system contains an ideal gas at a pressure of 1.5 105 pa.

Physics

1 answer:

Sedbober [7]2 years ago

5 0

The change in the internal energy of the ideal gas is determined as -28 J.

The work done on the ideal gas is calculated as follows;

w = -PΔV

w = -1.5 x 10⁵(0.0006 - 0.0002)

w = -60 J

<h3>Change in the internal energy of the gas</h3>

ΔU = w + q

ΔU = -60J + 32 J

ΔU = -28 J

Thus, the change in the internal energy of the ideal gas is determined as -28 J.

Learn more about internal energy here: brainly.com/question/23876012

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