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Andrews [41]
4 years ago
7

One kilogram of water fills a 150 L rigid container at an initial pressure of 2MPa. The container is cooled to 40 oC. Find the i

nitial temperature and final pressure of the water.

Engineering
2 answers:
Scrat [10]4 years ago
6 0

Explanation:

Below is an attachment containing the solution.

Tatiana [17]4 years ago
5 0

Answer:

The initial temperature is 649 K (376 °C).

The final pressure is 0.965 MPa

Explanation:

From the ideal gas equation

PV = nRT

P is the initial pressure of water = 2 MPa = 2×10^6 Pa

V is intial volume = 150 L = 150/1000 = 0.15 m^3

n is the number of moles of water in the container = mass/MW = 1000 g/18 g/mol = 55.6 mol

R is gas constant = 8.314 m^3.Pa/mol.K

T (initial temperature) = PV/nR = (2×10^6 × 0.15)/(55.6 × 8.314) = 649 K = 649 - 273 = 376 °C

From pressure law,

P1/T1 = P2/T2

P2 (final pressure) = P1T2/T1

T2 (final temperature) = 40 °C = 40 + 273 = 313 K

P1 (initial pressure) = 2 MPa

T1 (initial temperature) = 649 K

P2 = 2 × 313/649 = 0.965 MPa

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maks197457 [2]
  1. The height of the tower is equal to 78.4 meters.
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<h3>How to determine the height of the tower?</h3>

In order to determine the height of the tower, we would apply the second equation of motion and assume that the downward motion is negative.

Mathematically, the second equation of motion is given by this formula:

S = ut + ½gt²

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In order to calculate the bearing's impact velocity, we would apply the first equation of motion:

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V = 0 - 9.8(4.0)

Impact velocity, V = 39.2 m/s.

Read more on velocity here: brainly.com/question/19365526

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Complete Question:

Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower, called a shot tower, and solidify as they fall.

a. If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be?

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