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Nadusha1986 [10]
3 years ago
15

Problem 4

Chemistry
1 answer:
Hunter-Best [27]3 years ago
3 0
<h3>Answer:</h3>

1.93 g

<h3>Explanation:</h3>

<u>We are given;</u>

The chemical equation;

2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l) ΔH = -3120 kJ​

We are required to calculate the mass of ethane that would produce 100 kJ of heat.

  • From the equation given;
  • 2 moles of ethane burns to produce 3120 Kilo joules of heat
  • Therefore;

Number of moles that will produce 100 kJ will be;

= (2 × 100 kJ) ÷ 3120 kJ)

= 0.0641 moles

  • But, molar mass of ethane is 30.07 g/mol

Therefore;

Mass of ethane = 0.0641 moles × 30.07 g/mol

                          = 1.927 g

                          = 1.93 g

Thus, the mass of ethane that would produce 100 kJ of heat is 1.93 g

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When you have dominant allele T, recessive for t, T for tall and t for short, what will be phenotype for Tt?
Dmitry_Shevchenko [17]

Answer:

TT and Tt genotypes both expressed the tall phenotype because the T is dominant to t. Only the tt genotype expressed the short phenotype.

Explanation:

Hope this helped!

8 0
3 years ago
A sample originally contains 24 grams of a radioactive isotope. After 18 days, 18.8 grams of the isotope remain in the sample. W
LenKa [72]
Around 36 or 37 days, because of the decimal
8 0
2 years ago
During photosynthesis, plant leaves take in carbon dioxide through _______ in their leaves. a stomata b xylem c phloem
Iteru [2.4K]
<h3>Answer:</h3>

Stomata

<h3>Explanation:</h3>
  • Photosynthesis refers to the process that takes place in green plants and some algae.
  • During the process, water and carbon dioxide are converted to nutrients or organic compounds using energy from sunlight.
  • The process takes place in the chloroplast on the leaves of green plants.
  • The water used during photosynthesis comes from the soil and then transported by xylem tissue to the leaves where the process takes place.
  • Carbon dioxide enters the leaves through the stomata which are the sites for gaseous exchange.
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7 0
3 years ago
in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125
PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

3 0
3 years ago
For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
ladessa [460]

<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643 1/s.
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K = 0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

4 0
3 years ago
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