Answer : The time taken for the reaction is, 28 s.
Explanation :
Expression for rate law for first order kinetics is given by :
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 0.0632
t = time taken for the process = ?
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount or concentration of the reactant = 1.28 M
![[A]](https://tex.z-dn.net/?f=%5BA%5D)
= amount or concentration left time 't' = 
Now put all the given values in above equation, we get:
Therefore, the time taken for the reaction is, 28 s.
Answer:
The purpose of selective breeding is to develop livestock whose desirable traits have strong heritable components and can therefore be propagated
The electronic configuration [the valence electrons is known by the last no after
Answer:
Percent yield = 94.5%
Theoretical yield = 26.89 g
Explanation:
Given data:
Mass of copper = 12.5 g
Mass of copper chloride produced = 25.4 g
Theoretical yield = ?
Percent yield = ?
Solution:
Cu + Cl₂ → CuCl₂
Number of moles of Copper:
Number of moles = mass/ molar mass
Number of moles = 12.5 g/ 63.55 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of copper with copper chloride.
Cu : CuCl₂
1 : 1
0.2 : 0.2
Theoretical yield:
Mass of copper chloride:
Mass = Number of moles × molar mass
Mass = 0.2 mol × 134.45 g/mol
Mass = 26.89 g
Percent yield:
Percent yield = Actual yield / theoretical yield × 100
Percent yield = 25.4 g/26.89 g × 100
Percent yield = 94.5%
