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3 years ago

The model represents a fluorine (F) atom. What is the mass of the atom?

Physics

1 answer:

castortr0y [4]3 years ago

8 0

Answer:

Explanation:

The mass of an atom is found in the nucleus: number of protons + number of neutrons; 9 + 10 = 19

The mass number of fluorine is 19

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What is the mass of an atom that has 2 protons, 3 neutrons, and 2 electrons

marusya05 [52]

You can find the mass of an atom by adding the number of protons and neutrons. In this case the atom has 2 protons and 3 neutrons so the mass is 5.

3 0

4 years ago

A floating ice block is pushed through a displacement d = (23 m) i - (9 m) j along a straight embankment by rushing water, which

Sav [38]

Answer:

Work = 5941 J

Explanation:

As we know that work done is given by the equation

$W = F. d$

here we know that

$F = (200 N)\hat i - (149 N) \hat j$

also we have

$d = (23m) \hat i - (9 m)\hat j$

now from above formula we have

$W = (200 N\hat i - 149 N \hat j).(23 m\hat i - 9m \hat j)$

$W = 5941 J$

3 0

3 years ago

Read 2 more answers

As part of a daring rescue attempt, the Millennium Eagle coasts between a pair of twin asteroids, as shown in the figure below w

Luden [163]

The correct answer is 3 wiv 2=6

4 0

3 years ago

What did solomon asch discover in his famous experiment on judging the lengths of lines?

BaLLatris [955]

Answer:

Asch (1956) found that group size influenced whether subjects conformed. The bigger the majority group (no of confederates), the more people conformed, but only up to a certain point.

Explanation:

4 0

3 years ago

A loaded ore car has a mass of 950 kg. and rolls on rails ofnegligible friction. It starts from rest ans is pulled up a mineshaf

stiks02 [169]

(a) 10241 W

In this situation, the car is moving at constant speed: this means that its acceleration along the direction parallel to the slope is zero, and so the net force along this direction is also zero.

The equation of the forces along the parallel direction is:

$F - mg sin \theta = 0$

where

F is the force applied to pull the car

m = 950 kg is the mass of the car

$g=9.8 m/s^2$ is the acceleration of gravity

$\theta=30.0^{\circ}$ is the angle of the incline

Solving for F,

$F=mg sin \theta = (950)(9.8)(sin 30.0^{\circ})=4655 N$

Now we know that the car is moving at constant velocity of

v = 2.20 m/s

So we can find the power done by the motor during the constant speed phase as

$P=Fv = (4655)(2.20)=10241 W$

(b) 10624 W

The maximum power is provided during the phase of acceleration, because during this phase the force applied is maximum. The acceleration of the car can be found with the equation

$v=u+at$

where

v = 2.20 m/s is the final velocity

a is the acceleration

u = 0 is the initial velocity

t = 12.0 s is the time

Solving for a,

$a=\frac{v-u}{t}=\frac{2.20-0}{12.0}=0.183 m/s^2$

So now the equation of the forces along the direction parallel to the incline is

$F - mg sin \theta = ma$

And solving for F, we find the maximum force applied by the motor:

$F=ma+mgsin \theta =(950)(0.183)+(950)(9.8)(sin 30^{\circ})=4829 N$

The maximum power will be applied when the velocity is maximum, v = 2.20 m/s, and so it is:

$P=Fv=(4829)(2.20)=10624 W$

(c) $5.82\cdot 10^6 J$

Due to the law of conservation of energy, the total energy transferred out of the motor by work must be equal to the gravitational potential energy gained by the car.

The change in potential energy of the car is:

$\Delta U = mg \Delta h$