The equations used to find the measure of each angle in degrees is x + y = 90 and x = 6y - 1
The two complementary angles are 77 degrees and 13 degrees
<em><u>Solution:</u></em>
Given that two angles are complementary angles
Complementary angles are two angles whose sum is 90 degrees
Let one of the angle be "x" and the other angle be "y"
Therefore,
x + y = 90 ------ eqn 1
Also given that,
One angle is one less than six times the measure of another
one angle = six times the other angle - 1
x = 6y - 1 ------ eqn 2
Substitute eqn 2 in eqn 1
6y - 1 + y = 90
Thus the above equation is used to find the measure of each angle in degrees
Solve the above equation
6y + y - 1 = 90
7y - 1 = 90
7y = 91
y = 13
Substitute y = 13 in eqn 2
x = 6(13) - 1
x = 78 - 1
x = 77
Thus the two complementary angles are 77 degrees and 13 degrees
What do you mean
Could you please insert an equation or a problem
Answer:
QSR = 68º
Step-by-step explanation:
TSQ + QSR = TSR
15x + (10x - 2) = 173
Combine like terms
25x = 175
Divide both sides by 25
x = 7
QSR = 10x - 2
QSR = 10(7) - 2
QSR = 68º
